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2 years ago

Tonya has a box that measures 12 cm by 7 cm by 19cm. what is the volume of the box. Please help

Mathematics

1 answer:

kaheart [24]2 years ago

4 0

Answer: 1,596 cubic cm. To find the volume, you need to multiply all the three sides given.

Step-by-step explanation:

12cm * 7 cm* 19cm = 1596 cm^3

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Solve using the elimination method. show your work 2x - y = 6 x + y = 6

bekas [8.4K]

Answer:

x=4, y=2

Step-by-step explanation:

2x - y = 6

x + y = 6

Add these together to eliminate y

2x - y = 6

x + y = 6

-----------------

3x = 12

Divide by 3

3x/3 = 12/3

x=4

But we still need y

x+y =6

4+y =6

Subtract 4 from each side

4+y-4 = 6-4

y=2

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2 years ago

Sandy grew 8 turnips joan grew 6 turnips how many turnips did they grow in all

kumpel [21]

8 turnips + 6 turnips = 14 turnips together

6 0

3 years ago

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What's the answer to this

lyudmila [28]

8(14-9)+5
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2
3. + 6

8(5)+5
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9 + 6

40 + 5
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45
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3 years ago

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :

For the first parenthesis:

$x^{2}+6x+b^{2}$

We can rewrite this as:

$x^{2}+2(3)x+b^{2}$

Hence in this case $b=3$ and $b^{2}=9$ :

$x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}$

For the second parenthesis:

$y^{2}-8y+b^{2}$

We can rewrite this as:

$y^{2}-2(4)y+b^{2}$

Hence in this case $b=-3$ and $b^{2}=9$ :

$y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}$

Then, equation (5) is rewritten as follows:

$(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16$ (6)

Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.

Rearranging:

$(x-3)^{2}+(y-4)^{2}=100$ (7)

At this point we have the circle equation in the center radius form $(x-h)^{2} +(y-k)^{2}=r^{2}$

Hence:

$h=-3$

$k=4$

$r=\sqrt{100}=10$

8 0

3 years ago

George has a small coin collection. He has collected 16 gold coins, 28 silver coins, 32 copper coins, and4 bronze coins. At a f

romanna [79]

Total number of coin that George has
16 + 28 + 32 + 4 = 80 coins
total number of coins sold by George
= 15% of 80
= 15/100 X 80
= 12 coins (ans)

8 0

3 years ago

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