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2 years ago

Tonya has a box that measures 12 cm by 7 cm by 19cm. what is the volume of the box. Please help

Mathematics

1 answer:

kaheart [24]2 years ago

4 0

Answer: 1,596 cubic cm. To find the volume, you need to multiply all the three sides given.

Step-by-step explanation:

12cm * 7 cm* 19cm = 1596 cm^3

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(2.3 x 105)(1.5 x 104) in scientific notation plssss ASAP

zhenek [66]

By using scientific notation we calculated (2.3 $\times$ 10⁵)(1.5 $\times$ 10⁴) we got 345 $\times$ 10⁷.

Given that,

(2.3 $\times$ 10⁵)(1.5 $\times$ 10⁴)

By using scientific notation

The scientific notation allows us to express extremely large or extremely small numbers by multiplying them by single-digit integers and by 10 raised to the power of the corresponding exponent. The exponent is either positive or negative depending on how big or little the number is.

Now, we calculate

(2.3 $\times$ 10⁵)=2.5 $\times$ 100000=230000

(1.5 $\times$ 10⁴)=1.5 $\times$ 10000=15000

Now,

=230000 $\times$ 15000

=3450000000

=345 $\times$ 10⁷

Therefore, By using scientific notation we calculated (2.3 $\times$ 10⁵)(1.5 $\times$ 10⁴) we got 345 $\times$ 10⁷.

To learn more about scientific notation visit: brainly.com/question/18073768

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3 0

1 year ago

The cost of 1 m ribbon is ₹ 75. Find the cost of 7/5 metres of ribbon

Margaret [11]

Given that

The cost of 1 m ribbon = Rs.75

The cost of 7/5 m ribbon

→ (7/5)×75

→ (7×75)/5

→7×15

→₹ 105

The cost of 7/5 m ribbon is ₹105.

8 0

2 years ago

True or false? A figure that has opposite sides with equal lengths and equal slopes and diagonals with slopes that are negative

Alex787 [66]

Answer:

False.

Step-by-step explanation:

The diagonals are at right angles ( because of the negative reciprocal slopes)

so it could be a square or a rhombus.

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%7B3x%7D%5E%7B3%7D%20%20%5Ctimes%204%20%7By%7D%5E%7B5%7D%20%20%5Cdiv%20%20%7B8y%7D%5E%7B2%7

garik1379 [7]

The answer is 12x3y5 divided by 8x15x5y2

6 0

3 years ago

Sin4x.sin5x+sin4x.sin3x-sin2x.sinx=0

andreev551 [17]

Recall the angle sum identity for cosine:

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

cos(x - y) = cos(x) cos(y) + sin(x) sin(y)

==> sin(x) sin(y) = 1/2 (cos(x - y) - cos(x + y))

Then rewrite the equation as

sin(4x) sin(5x) + sin(4x) sin(3x) - sin(2x) sin(x) = 0

1/2 (cos(-x) - cos(9x)) + 1/2 (cos(x) - cos(7x)) - 1/2 (cos(x) - cos(3x)) = 0

1/2 (cos(9x) - cos(x)) + 1/2 (cos(7x) - cos(3x)) = 0

sin(5x) sin(-4x) + sin(5x) sin(-2x) = 0

-sin(5x) (sin(4x) + sin(2x)) = 0

sin(5x) (sin(4x) + sin(2x)) = 0

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

Rewrite the equation again as

sin(5x) (2 sin(2x) cos(2x) + sin(2x)) = 0

sin(5x) sin(2x) (2 cos(2x) + 1) = 0

sin(5x) = 0 or sin(2x) = 0 or 2 cos(2x) + 1 = 0

sin(5x) = 0 or sin(2x) = 0 or cos(2x) = -1/2

sin(5x) = 0 ==> 5x = arcsin(0) + 2nπ or 5x = arcsin(0) + π + 2nπ

… … … … … ==> 5x = 2nπ or 5x = (2n + 1)π

… … … … … ==> x = 2nπ/5 or x = (2n + 1)π/5

sin(2x) = 0 ==> 2x = arcsin(0) + 2nπ or 2x = arcsin(0) + π + 2nπ

… … … … … ==> 2x = 2nπ or 2x = (2n + 1)π

… … … … … ==> x = nπ or x = (2n + 1)π/2

cos(2x) = -1/2 ==> 2x = arccos(-1/2) + 2nπ or 2x = -arccos(-1/2) + 2nπ

… … … … … … ==> 2x = 2π/3 + 2nπ or 2x = -2π/3 + 2nπ

… … … … … … ==> x = π/3 + nπ or x = -π/3 + nπ

(where n is any integer)

5 0

2 years ago