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igor_vitrenko [27]
3 years ago
9

The mean of a list of test scores is 80. Adding an additional test score of 92 caused the mean to rise to 82. After this additio

nal, how many total test are in the list
Mathematics
1 answer:
miv72 [106K]3 years ago
4 0

Answer:

6

Step-by-step explanation:

The mean of a list of test scores is 80

Adding an additional test score of 92 caused the mean to rise to 82

To find:

After this additional, how many total test are in the list ?

Solution:

Let the total number of test at first = n

And sum of total score = S

As we know, mean = \frac{sum \ of \ total \ observation}{number\  of \ total\  observation}

                    80= \frac{S}{n} \\

Multiplying both sides by n

80n=S

Now, as adding an additional test score of 92 caused the mean to rise to 82,

S+92=82\times(n+1)\\80n +92 = 82n+82           \  (given \ S =80n)

80n-82n =82-92\\-2n=-10

By dividing both sides by minus ( - )

2n =10

By dividing both sides by 2

n =5

Thus, total number of test at first = n = 5

And, after this additional score added, total number of tests are n+1=6

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Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that \mu = 35000, \sigma = 7000

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

Z = \frac{X - \mu}{\sigma}

-1.88 = \frac{X - 35000}{7000}

X - 35000 = -1.88*7000

X = 21840

The designed life should be of 21,840 vehicle miles.

3 0
2 years ago
Solve for x in the equation x²-12x+59=0
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mean

x = 6 + i \sqrt{23}

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Answer:

Y= -8

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Step-by-step explanation:

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And could someone please help me with this one please
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Answer:

C

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

here (h, k) = (5, 2), thus

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To find a substitute (4, - 3) into the equation

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  = - 5x² + 50x - 123 ← in standard form

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