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aalyn [17]
2 years ago
15

Help me plz i’ll give extra points

Mathematics
1 answer:
PtichkaEL [24]2 years ago
4 0
The answer to your question is most likely A
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What are the slope and the y-intercept of the linear function that is represented by the equation y=-10x+1?
Alenkasestr [34]
Linear functions can be written in the form y=mx+b, where:
y is a y coordinate on the line
m is the slope of the line
x is the x coordinate on the line that corresponds with the y coordinate in the equation
b is the y-intercept of the line

So for the equation y=-10x+1:
m=-10 and b=1 so the slope of the line is -10, and the y-intercept is 1. Your answer is B.
5 0
2 years ago
Read 2 more answers
Find the value of x.<br> 2x<br> 120°<br> 700<br> A. 55<br> B. 35<br> C. 25<br> D. 10
monitta

Answer:

for this question you need to take the 12p and 700 and add then dived by 2x which then gives you your answer

7 0
3 years ago
Read 2 more answers
Look at the picture below to answer. If u answer correctly i will mark you as brainliest!
wlad13 [49]

Answer:

A

Step-by-step explanation:

The points are similar

4 0
2 years ago
Find the vertical and horizontal asympotote for (×-2) (×+3)/ (2×+2)
nekit [7.7K]

\bf \cfrac{(x-2)(x+3)}{2x+2}\implies \cfrac{x^2+x-6}{2x+2}~~ \begin{array}{llll} \leftarrow \textit{2nd degree polynomial}\\ \leftarrow \textit{1st degree polynomial} \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{vertical asymptote}}{2x+2=0}\implies 2x=-2\implies x=-\cfrac{2}{2}\implies x=-1


when the degree of the numerator is greater than the denominator's, then it has no horizontal asymptotes.


quick note:

when the degree of the numerator is 1 higher than the degree of the denominator, then it has an slant-asymptote, so this one has a slant-asymptote.

6 0
2 years ago
A man buys six books from the store and a preferred reader discount card for $20. Later that day, he goes and buys five more boo
amid [387]

Answer:

Step-by-step explanation: i think it would be 8.36

5 0
2 years ago
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