The box plot shows the number of cousins students in Mr. Myer's class have. Which

Mathematics

1 answer:

AnnZ [28]3 years ago

6 0

Answer:

We choose C

The spread from the lower quartile to the median is greater than the spread from the median to the upper quartile.

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one. Because I answered this question once in Brainly

Please have a look at the attached photo

In the photo, we know that:

Median: 7
Upper quartile: 9
Lower quartile: 4
Interquartile range: 9 - 4 = 5
Lower quartile to median: 7 - 4 = 3
Upper quartile to median: 9 - 7 = 2

Let analyse 4 answers:

A. Wrong, Lower quartile to median is more than Uper quartile to median

B. Wrong

C. True

D. Wrong

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The graphs of the function f (given in blue) and g (given in red) are plotted above. Suppose that u(x)=f(x)g(x) and v(x)=f(x)/g(

Rus_ich [418]

U(x) = f(x).(gx)
v(x) = f(x) / g(x)

Use chain rule to find u(x) and v(x).

u '(x) = f '(x) g(x) + f(x) g'(x)

v ' (x) = [f '(x) g(x) - f(x) g(x)] / [g(x)]^2

The functions given are piecewise.

You need to use the pieces that include the point x = 1.

You can calculate f '(x) and g '(x) at x =1, as the slopes of the lines that define each function.

And the slopes can be calculated graphycally as run / rise of each graph, around the given point.

f '(x) = slope of f (x); at x = 1, f '(1) = run / rise = 1/1 = 1

g '(x) = slope of g(x); at x = 1, g '(1) = run / rise = 1.5/ 1 = 1.5

You also need f (1) = 1 and g(1) = 2

Then:

u '(1) = f '(1) g(1) + f(1) g'(1) = 1*2 + 1*1.5 = 2 + 1.5 = 3.5

v ' (x) = [f '(1) g(1) - f(1) g(1)] / [g(1)]^2 = [1*2 - 1*1.5] / (2)^2 = [2-1.5]/4 =

= 0.5/4 = 0.125

Answers:
u '(1) = 3.5
v '(1) = 0.125

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