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rjkz [21]
3 years ago
5

Pls help me with this question it's due today

Mathematics
2 answers:
Fantom [35]3 years ago
8 0

Answer:

(2,1)

HOPE THIS HELPS

-Todo <3

Step-by-step explanation:

2x+(x-1)=5

3x-1=5

  +1  +1

3x=6

x=2

y=2-1

y=1

ryzh [129]3 years ago
7 0

Answer:

x=2

y=1

Step-by-step explanation:

You need to substitute y=x-1 into the top equation

2x+(x-1)=5

3x-1=5

3x=6

x=6/3

x=2

substitute x back into y=x-1

y=2-1

y=1

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Find the area of this irregular polygon.
Rainbow [258]

Answer:

970m^{2}

Step-by-step explanation:

This polygon can be divided in two figures: one is a triangle, an the other one is a square.

We'll begin calculating the triangle's area, using the following formula:

At= \frac{b.h}{2}

Where:

H= height = 30 m

B = 9 m + 9 m + 20 m = 38 m

As you can see, I added both sides of the triangle that measure 9 m and also the lenght of the square that measures 20 m! This added up is what the base of the triangle measures on total.

At= \frac{38 m .30 m}{2}

At= \frac{1140 m^{2} }{2}

At= 570 m^{2}

Now we are going to calculate the square's area, that is much more simple:

As= L^{2}

Where:

L=20 m

As= (20 m)^{2} = 400m^{2}

To know the whole figure's area, we add up both areas:

A = At+As = 570m^{2} +400m^{2}=970m^{2}

3 0
3 years ago
What is the vertex of f(x) = 2 ( x- 5)^2 +13
andrew-mc [135]
The answer is NO SOLUTION I hope
8 0
3 years ago
Solve for b:<br>10abc - 2d = 3d​
Kay [80]

Answer:

b = d/2ac

Step-by-step explanation:

7 0
3 years ago
What is the value of x?<br> 3/5x – 1/3 x = x – 1
Aleks04 [339]
The first step to solving this is to multiply both sides of the equation by 15.
9x - 5x = 15x - 15
Collect all of the like terms on the left side of the equals sign.
4x = 15x - 15
Move the variable to the left side of the equation and change its sign.
4x - 15x = -15
Now collect the like terms on the left side of the equation for the second time.
-11x = -15
Lastly,, divide both sides of the equation by -11 to get your final answer.
\frac{15}{11}
This means that the correct answer to your question is \frac{15}{11},, or 1\frac{4}{11} simplified.
Let me know if you have any further questions
:)
6 0
3 years ago
Find all rational zeros of the polynomial
rjkz [21]

x^3+x^2-5x+3=x^3+3x^2-2x^2-6x+x+3\\\\=(x^3-2x^2+x)+(3x^2-6x+3)=x(x^2-2x+1)+3(x^2-2x+1)\\\\=(x^2-2x+1)(x+3)=\underbrace{(x^2-2(x)(1)+1^2)}_{(a-b)^2=a^2-2ab+b^2}(x+3)=(x-1)^2(x+3)\\\\P(x)=0\iff(x-1)^2(x+3)=0\iff(x-1)^2=0\ \vee\ (x+3)=0\\\\x-1=0\ \vee\ x-1=0 \vee\ x+3=0\\\\x=1\ \vee\ x=1\ \vee\ x=-3\\\\Answer:\ \boxed{x_1=1,\ x_2=1,\ x_3=3}

4 0
3 years ago
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