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3 years ago

Answers to this question Please ?? Thank You

Mathematics

1 answer:

Olenka [21]3 years ago

8 0

The answer is c because he begins at 3 points. He then loses 9. So subtract 9 from 3 and you end up with -6

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Write a ratio to express the number of people who preferred WANR to those who preferred WCLM.

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11:12 is the answer to your question

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Explain why you do not have to do computing to solve 15×0×(13+7)

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Prove ABE congruent ACD

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In a newspaper poll concerning violence on television, 589 people were asked, "What is your opinion of the amount of violence on

abruzzese [7]

Answer:

(a) $P(Y'|M)\approx 0.3297$

(b) $P(Y|M')\approx 0.8323$

Step-by-step explanation:

Given table is

Yes No Don't Know Total

Men 162 92 25 279

Women 258 41 11 310

Total 420 133 36 589

According the the conditional probability, if A and B are two event then

$P(A|B)=P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}$

We need to find the following probabilities.

Let Y is the event "saying yes," and M is the event "being a man."

(a)

$P(Y'|M)=\frac{P(Y'\cap M)}{P(M)}$

$P(Y'|M)=\frac{\frac{92}{589}}{\frac{279}{589}}$

$P(Y'|M)=\frac{92}{279}$

$P(Y'|M)=0.329749103943$

$P(Y'|M)\approx 0.3297$

(b)

$P(Y|M')=\frac{P(Y\cap M')}{P(M')}$

$P(Y|M')=\frac{\frac{258}{589}}{\frac{310}{589}}$

$P(Y|M')=\frac{258}{310}$

$P(Y|M')=0.832258064516$

$P(Y|M')\approx 0.8323$

(c)

$P(Y'|M')=\frac{P(Y'\cap M')}{P(M')}$

$P(Y'|M')=\frac{\frac{41}{589}}{\frac{310}{589}}$

$P(Y'|M')=\frac{41}{310}$

$P(Y'|M')=0.132258064516$

$P(Y'|M')\approx 0.1323$

5 0

3 years ago

The weights of professional wrestlers are approximately normally distributed with a mean of 220 pounds and a standard deviation

nikdorinn [45]

Answer:

1.6%

Step-by-step explanation:

The cumulative distribution function (CDF) of a random variable X is denoted by F(x), and is defined as

F(x) = P(X ≤ x). where x is the largest possible value of X that is less than or equal to x

z = (x-μ)/σ,

where:

x is the raw score = 205

μ is the population mean, = 220 pounds

σ is the population standard deviation = 7 pounds

205 -220/7

z = -15/7

z = -2.1428571429

Using the normal cdf function on your graphing calculator,the cumulative distribution is

normalcdf( -2.1428571429, 100)

= 0.01606229

In percent form = 0.01606229 × 100

= 1.6%

5 0

2 years ago