(3x-2)^2
squares area is 2 times its side length, since all the sides are the same. if the side length is 3x-2, take its second power
There are 2 ways that spring to mind.
One is to use the definition of the derivative at a point:
In this case, 
and 
. Then
- - -
If you don't know about derivative yet (I would think you do, considering this is for a midterm in AP Calc, but I digress), the other way is to rely on algebraic manipulation. Multiply the numerator and denominator by the conjugate of the numerator to get
This is continuous at 
, so the limit is the value of the expression at :
Answer:
Only:
B. x=7
D. x=0
Step-by-step explanation:
Substitute the answers in the formula and only 7 and 0 will work.
Answer:
x = 28 (So it takes 28 hours for the temperature to reach 0°C.)
y = -70 (So the temperature when the experiment begins is −70°C.)
Step-by-step explanation:
To find the the x value, you remove the y value or replace it with 0.
0 = 5/2x - 70
Next you move the variable.
70 (2/5) = x (multiply 70 by 2 to get 140 and divide that by 5)
And now you simplify to get:
28
To find the y value, you remove the x value or replace it with 0.
y = 0 - 70
And now you simplify to get:
-70
x = 28
y = -70
The answer for this problem is 70
