Please help me guys please I’m stuck on this

Do you like 1----10<br> cuteeeeee

Sphinxa [80]

Answer:

what

Step-by-step explanation:

6 0

3 years ago

Using the compensation strategy. 4,153+2,988

makvit [3.9K]

4,153+2,988
-12 +12
4,141+3,000

3,000+4,000=7,000
7,000+141=7,141

5 0

3 years ago

Which graph shows three points that represent equivalent ratios?<br> hurry plz

pshichka [43]

Answer:

it will be c because you see the points on the grid if its wrong my bad

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The mean finish time for a yearly amateur auto race was 186.32 minutes with a standard deviation of 0.305 minute. The winning c

uranmaximum [27]

Complete Question

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.305 minute. The winning car, driven by Roger, finished in 185.85 minutes. The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

Find their respective z-scores.

Who had the more convincing victory?

A. Roger had a more convincing victory because of a higher z-score.

B. Karen a more convincing victory because of a higher z-score.

C. Roger had a more convincing victory, because of a lower z-score.

D. Karen a more convincing victory because of a lower z-score.

Answer:

The correct option is D

Step-by-step explanation:

From the question we are told that

The mean of the current year is $\mu_c = 186.32 \ minutes$

The standard deviation is $\sigma_c = 0.305 \ minutes$

The time taken by the winning car for the current year is $x = 185.85 \ minutes$

The mean of the previous year is $\mu_p = 110.7 \ minutes$

The standard deviation the previous year is $\sigma_p = 0.115 \ minutes$

The time taken by the winning car for the previous year is $y = 110.48 \ minutes$

Generally the z-score for current year is mathematically evaluated as

$z_c = \frac{x- \mu_c}{\sigma_c }$

=> $z_c = \frac{ 185.85- 186.32}{0.305 }$

=> $z_c = -1.536$

Generally the z-score for previous year is mathematically evaluated as

$z_p = \frac{y- \mu_p}{\sigma_p }$

=> $z_p = \frac{ 110.48-110.7}{0.115 }$

=> $z_p = -1.913$

From the value obtained we see that $z_p < z_c$ , Hence Karen had a more convincing victory because of the lower z -score.

5 0

2 years ago

how does kasey situation change . the function? write a new function k(t) to represent kaseys account balance to any year t

rjkz [21]

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6 0

2 years ago