The Volume of air needed for a spherical balloon of radius 4 inch and circumference 8π is 85.3 cubic inch
<h3>Volume of Sphere</h3>
Given Data
Let us find radius
circumference = 2πr
8π = 2πr
8 = 2r
r = 8/2
r = 4 inch
Let us find the volume of the sphere
Volume = 4/3πr^3
Volume = 4/3* π*4^3
Volume = 4/3*π64
Volume = 256π/3
Volume = 85.3 cubic inch
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Answer:
b
Step-by-step explanation:
Answer:
160 lbs = 72.57kg
Step-by-step explanation:
This can be solved as a rule of three problem.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.
Unit conversion problems, like this one, is an example of a direct relationship between measures.
Each lb has 0.45kg. How many kg are there in 160lbs. So:
1lb - 0.45kg
160 lbs - xkg

kg
160 lbs = 72.57kg
Answer:
d = 
Step-by-step explanation:
The distance formula is d=
.
6 is
, 9 is
, 3 is y
, and -2 is y
.
When you plug these into the formula, you get d = 
Answer:
-2/3
Step-by-step explanation: