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3 years ago

How do you turn 32/3 into a mixed number

Mathematics

2 answers:

Leokris [45]3 years ago

7 0

Hello!

In order to convert an improper fraction into a mixed number you must:

1) Find out how many times 3 goes into 32. 3 goes into 32 10 times.

2) With the remaining 2 put in the numerator spot and leave the three in the same spot

Your answer should be 10 2/3.

I hope it helps!

Natalka [10]3 years ago

6 0

You divide the numerator by the denominator, meaning you divide 32 by 3.

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Line L1 has the equation 3x-30y=6 Express the equation of L1 in the slope-intercept form

charle [14.2K]

Y= 1/10x + 2/10 is what you are left with once the equation is simplified

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3 years ago

F.8=8f? What is the answer

sveta [45]

Hey there!

f.8=8f

0.8f = 8f

SUBTRACT 8f to BOTH SIDES

0.8f - 8f = 8f - 8f

SIMPLIFY IT!

-7.2f = 0

DIVIDE -7.2 to BOTH SIDES

-7.2f/-7.2 = 0/-7.2

CANCEL out3 -7.2/-7.2 because it give you 1

KEEP: 0/-7.2 because it help solve for the f-value

NEW EQUATION: f = 0/-7.2

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f = 0

Therefore, your answer is: f = 0

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2 years ago

Rewrite the expression with a perfect square: x^2 - 14x + 11

nikitadnepr [17]

Factoring x2-14x+11

The first term is, x2 its coefficient is 1 .

The middle term is, -14x its coefficient is -14 .

The last term, "the constant", is +11

Step-1 : Multiply the coefficient of the first term by the constant 1 • 11 = 11

Step-2 : Find two factors of 11 whose sum equals the coefficient of the middle term, which is -14 .

-11 + -1 = -12 -1 + -11 = -12 1 + 11 = 12 11 + 1 = 12

Observation : No two such factors can be found

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2 years ago

Write the equation in vertex form and then find the vertex, focus, and directrix of a parabola with equation x=y^2+18y-2

kakasveta [241]

Answer:

Part 1) The vertex is the point (-83,-9)

Part 2) The focus is the point (-82.75,-9)

Part 3) The directrix is $x=-83.25$

Step-by-step explanation:

step 1

Find the vertex

we know that

The equation of a horizontal parabola in the standard form is equal to

$(y - k)^{2}=4p(x - h)$

where

p≠ 0.

(h,k) is the vertex

(h + p, k) is the focus

x=h-p is the directrix

In this problem we have

$x=y^{2} +18y-2$

Convert to standard form

$x+2=y^{2} +18y$

$x+2+81=y^{2} +18y+81$

$x+83=(y+9)^{2}$

This is a horizontal parabola open to the right

(h,k) is the point (-83,-9)

The vertex is the point (-83,-9)

step 2

we have

$x+83=(y+9)^{2}$

Find the value of p

$4p=1$

$p=1/4$

Find the focus

(h + p, k) is the focus

substitute

(-83+1/4,-9)

The focus is the point (-82.75,-9)

step 3

Find the directrix

The directrix of a horizontal parabola is

$x=h-p$

substitute

$x=-83-1/4$

$x=-83.25$

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3 years ago

Given m 1= 65, find the measure of each missing angle.Givd your reasoning

lorasvet [3.4K]

Answer:

Step-by-step explanation:

Given:

m∠1 = 65°

Since. ∠1 and ∠2 are the angles of linear pair,

m∠1 + m∠2 = 180°

65° + m∠2 = 180°

m∠2 = 115°

m∠1 = m∠3 [Vertical angles]

m∠3 = 115°

Since, ∠1 and ∠4 is the linear pair of angles,

m∠1 + m∠4 = 180°

65° + m∠4 = 180°

m∠4 = 180 - 65 = 115°

m∠4 + m∠5 = 180° [Consecutive interior angles between the parallel lines]

115° + m∠5 = 180°

m∠5 = 180° - 115° = 65°

m∠5 + m∠6 = 180° [Linear pair of angles]

65° + m∠6 = 180°

m∠6 = 115°

m∠5 = m∠7 [Vertical angles]

m∠5 = m∠7 = 65°

m∠6 = m∠8 [Vertical angles]

m∠6 = m∠8 = 115°

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3 years ago