Question 11a)
We are given side BC equals to side CE and angle CBA equals to angle CED
We also know that angle ACB equals to angle ECD are equal (opposite angles properties)
We have enough information to deduce that triangle ABC and triangle CDE are equal by postulate Angle-Side-Angle (ASA)
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Question 11b)
We are given side AB equal to side ED, side BC equals to side EF, and side AC equals to side DF
We have enough information to deduce that triangle ABC and triangle DEF congruent by postulate Side-Side-Side (SSS)
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Question 11c)
We are given side AC equals to side DF, angle ABC equals to angle DEF, and angle BAC equals to angle EDF
We have enough information to deduce that triangle ABC congruent to triangle DEF by postulate Angle-Side-Angle (ASA)
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Question 11d)
We do not have enough information to tell whether this shape congruent or not
Answer:
ithe answer to your question is going to be c
Answer:
see explanation
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Given
y = x² - 6x + 3
To complete the square
add/subtract ( half the coefficient of the x- term)² to x² - 6x
y = x² + 2(- 3)x + 9 - 9 + 3
= (x - 3)² - 6 ← in vertex form
• If a > 0 then vertex is a minimum
• If a < 0 then vertex is a maximum
Here a = 1 > 0, thus
(3, - 6 ) is a minimum
Answer:
i put a graph in there
Step-by-step explanation:
18y + 9 = -12 + 18y
9=-12
I hope that’s right... I haven’t done this in ages
