13,822 to one significant figure is 10,000
623 to one significant figure is 600
14 to one significant figure is 10
10,000 times 600 = 6,000,000
6,000,000/10 = 600,000
Answer:
THIS IS YOUR ANSWER:
<em>✍️</em><em>HOPE</em><em> </em><em>IT HELPS</em><em> </em><em>YOU</em><em> </em><em>✍️</em>
I looked it up on google it is 1252
The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ==5
n=50
s orσ =5/=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
Learn more about probability at brainly.com/question/24756209
#SPJ4
There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?