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Diano4ka-milaya [45]
3 years ago
8

The square of a number exceeds that number by 12. What are the two possible solutions?

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
3 0
X^2=x+12
minus x+12 both sides
x^2-x-12=0
factor
(x-3)(x+4)=0
set each to zero

x-3=0
x=3

x+4=0
x=-4

x=3 or -4

answer is first one
shusha [124]3 years ago
3 0
<span>The square of a number exceeds that number by 12. What are the two possible solutions would e B i think

</span>
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