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3 years ago

The square of a number exceeds that number by 12. What are the two possible solutions?

2 answers:

3 0

X^2=x+12
minus x+12 both sides
x^2-x-12=0
factor
(x-3)(x+4)=0
set each to zero

x-3=0
x=3

x+4=0
x=-4

x=3 or -4

answer is first one

shusha [124]3 years ago

3 0

<span>The square of a number exceeds that number by 12. What are the two possible solutions would e B i think

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2 years ago

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natima [27]

$\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }$

$\large\underline{ \boxed{ \sf{✰\:Important\: point's }}}$

➢Given two lines are intersecting lines
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${ \rule{70mm}{2.9pt}}$

$\underline{ \boxed{ \sf{✵\: let's\: solve\:✵}}}$

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${ \rule{70mm}{2.9pt}}$

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2 years ago

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zimovet [89]

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A figure has a line of symmetry if we can draw a line through the figure, in such way that the line cuts the figure in exactly two equal halves.

Then any figure that can be cutin exactly two halves, is a correct answer to this question.

Then:

For a circle, the line of symmetry is the diameter of the circle.

For the square, the line of symmetry can be obtained by cutting the square with a line that is perpendicular to one of the sides, and cuts that side exactly on the midpoint.

For an equilateral triangle, the line of symmetry is the line that cuts any base in the midpoint and also passes through the opposite vertex.

Then all the figures are correct options, then the correct option is D

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3 years ago

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bearhunter [10]

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