3 years ago

The square of a number exceeds that number by 12. What are the two possible solutions?

2 answers:

3 0

X^2=x+12
minus x+12 both sides
x^2-x-12=0
factor
(x-3)(x+4)=0
set each to zero

x-3=0
x=3

x+4=0
x=-4

x=3 or -4

answer is first one

shusha [124]3 years ago

3 0

<span>The square of a number exceeds that number by 12. What are the two possible solutions would e B i think

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