Figure ABCD is translated down by 6 units:

1 answer:

3 0

The sides would still be the same. If the figure ABCD was a square, it would remain the same because all of the points are equally translated down 6 units. Whatever shape the original figure was, it will remain the same, just in a different location.

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Why would using a net and needing to know how to calculate surface area be an important part of designing a three-dimensional ob

son4ous [18]

Answer:

A net is a pattern made when the surface of a three-dimensional figure or solid is laid out flat showing each face of the figure. It is then possible to use the net to calculate the surface area of the solid. Surface Area of a Cube using Nets. A cube is a three-dimensional figure with six matching square faces.

Step-by-step explanation:

hope it helps

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3 years ago

The value of x must be greater than what?

alexandr402 [8]

Answer: I believe it would be the hypotenuse, i not to sure but I hope this helps in some way

Step-by-step explanation:

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2 years ago

Bob the builder is making 480kg of concrete mix

vichka [17]

To answer this item, we are first to determine the common factor between the amounts of the cement, sand, and gravel.

If we let x be this factor, the amount of the cement would be x. Similarly, the amount of sand is 3x, and lastly the amount of gravel is 4x. Then, we establish the equation that would let us relate the amounts.

x + 3x + 4x = 480

Simplifying,

8x = 480

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5 0

3 years ago

What is the smallest positive integer for x so that f(x)=200(2)* is greater than the value of g(x)=500x+400?

Goshia [24]

We have to functions, namely:

$f(x)=200(2)^{x} \ and \ g(x)=500x+400$

So the problem is asking for the smallest positive integer for $x$ so that $f(x)$ is greater than the value of $g(x)$ , that is:

$f(x)\ \textgreater \ g(x) \\ \therefore 200(2)^{x}\ \textgreater \ 500x+400$

Let's solve this problem by using the trial and error method:

$for \ x=1 \\f(1)=400 \\ g(1)=900 \\ Then \ f(1) \ \textless \ g(1) \\ \\ \\ for \ x=2 \\f(2)=800 \\ g(2)=1400\\ Then \ f(2)\ \textless \ g(2) \\ \\ \\ for \ x=3 \\f(3)=1600 \\ g(3)=1900 \\ Then \ f(3)\ \textless \ g(3) \\ \\ \\ for \ x=4 \\f(4)=3200 \\ g(4)=2400 \\ \boxed{Then \ f(4)\ \textgreater \ g(4)}$

So starting $x$ from 1 and increasing it in steps of one we find that:

$f(x)>g(x)$

when $x=4$

That is, the smallest positive integer for $x$ so that the function $f(x)$ is greater than $g(x)$ is 4.

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3 years ago

Change to fraction 336%

noname [10]

84/25 (84/25 = 3.36)
Hope to help
:D

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3 years ago

Read 2 more answers