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Arlecino [84]
3 years ago
11

Please help with this question I really need it right now please show work and please if you don't understand this question plea

se don't answer . Question number 12

Mathematics
1 answer:
Zina [86]3 years ago
8 0

Answer:a is the correct option

Step-by-step explanation:

The table is divided into columns for month, sales and expense

Total number of sales for four months is determined by adding up the sales for each month. It becomes

35.75+65.34+12.15+49.68= $162.92

Total number of sales for four months is determined by adding up the expenses for each month. It becomes

43.18+52.24+41.09+59.50=196.01

Profit or loss = total sales - total expenses

Therefore 162.92-196.01 = - $33.09

It's a loss because it is negative

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Idek what im doing<br> help please
Svetlanka [38]

Answer:

180 -88 = 92 degrees

Step-by-step explanation:

5 0
3 years ago
If
arlik [135]

Given:

In a right angle triangle θ is an acute angle and \tan\theta =\dfrac{3}{5}.

To find:

The value of \cos \theta.

Solution:

In a right angle triangle,

\tan \theta=\dfrac{Perpendicular}{Base}

We have,

\tan\theta =\dfrac{3}{5}

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.

By using Pythagoras theorem,

Hypotenuse=\sqrt{Perpendicular^2+base^2}

Hypotenuse=\sqrt{(3x)^2+(5x)^2}

Hypotenuse=\sqrt{9x^2+25x^2}

Hypotenuse=\sqrt{34x^2}

Hypotenuse=x\sqrt{34}

In a right angle triangle,

\cos \theta=\dfrac{Base}{Hypotenuse}

\cos \theta=\dfrac{5x}{x\sqrt{34}}

\cos \theta=\dfrac{5}{\sqrt{34}}

Therefore, the value of \cos \theta is \dfrac{5}{\sqrt{34}}.

8 0
3 years ago
A triangle is reduced. What is the perimeter of the reduced triangle, in inches.
algol13

Answer:

the perimeter is 36

Step-by-step explanation:

8 0
3 years ago
Last month Christopher practiced his violin for 16 hours and Patrick practiced his cello for 780 minutes how many more hours did
zysi [14]

Answer:

Christopher practiced 3  ore hors

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
3x-2y=-39 and x+3y=31 solution using elimination
Kobotan [32]
This is hard to write... I hope this makes sense to you...
3x-2y=-39
x+3y= 31
We want to use elimination therefor, we need to either get our x or our y to add together to get zero. 
To do this, we will multiply -3 to (x=3y=31) 
NEW EQUATION
3x-2y=-39 PLUS
-3x-9y= -93 Equals
Answer: -11y= -54 
y= 4.9
Plug in to solve for x (put new y in)
3x-2(4.9)=-39
x= -9.73 
5 0
4 years ago
Read 2 more answers
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