Answer:
Ben spent 9 dollars
Step-by-step explanation:
Answer:
<u>/</u><u> </u>3=<u>/</u><u> </u>5 { alternate anglea}
<u>/</u><u> </u>5+<u>/</u>6 =180° {straight angle}
<u>/</u><u> </u>6=180-26
<u>/</u><u> </u>6=154°
hope it helps
<h3>stay safe healthy and happy.</h3>
Answer:
should be after 10 years , $1967.15
Answer:
Step-by-step explanation:
4). This is an exponential function.
5). Let the equation of this function is,
f(x) = a(b)ˣ
Since, two points (-1, 4) and (0, 6) are lying on the graph of the function,
For (-1, 4),
4 = a(b)⁻¹
4 =
--------(1)
For (0, 6),
6 = a(b)⁰
a = 6
From equation (1),
4 = 
b =
= 1.5
Therefore, equation of the function will be,
f(x) = 6(1.5)ˣ
6). Now the value of f(-4) will be,
f(-4) = 6(1.5)⁻⁴
= 1.185

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:
| 2 -7 8 -3
<u>1 | 2 -5 3</u>
| 2 -5 3 0
<u> 1 | 2 -3 </u>
2 -3 0
So the factorization is (x-1)² (2x-3)=0. So:


Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:
| 1 -1 0 -4
<u>2 | 2 2 </u>
1 2 2 0
So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.


Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:
| 6 7 9 2
<u>-2 | -12 10 -2</u>
6 -5 1 0
So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

