CAN SOMEONE HELP ME PLEASE ASAP!?

You triple your account balance by making a deposit. Then you withdraw $28.50 from your bank account. Now your account is overdr

Crazy boy [7]

Answer:

Your original account balance before you made the deposit is $6

Step-by-step explanation:

Let x = your original account balance.

You triple your account balance by making a deposit. This means

New account balance = 3 × x = 3x

Then you withdraw $28.50 from your bank account. This means that you have $(3x - 28.5) left.

Now your account is overdrawn by $10.50. This means you have withdrawn beyond what you have in your account. Your new account balance is -$10.5. Therefore,

3x - 28.5 = - 10.5

3x = -10.5 + 28.5 = 18

x = 18/3 = 6

Your original account balance before you made the deposit is $6

8 0

3 years ago

EXPLAIN THE ERROR Cody was given two points (1/2,4) and (2/3,1), on a line and asked to create a linear equation in standard for

inessss [21]

Answer:

Cody made a mistake when calculating the slope of the line and this affected every other steps after than.

She divided -3 by 6 instead of -3 by 1/6

Step-by-step explanation:

Given

$(x_1,y_1) = (\frac{1}{2},4)$

$(x_2,y_2) = (\frac{2}{3},1)$

<em>See attached for steps</em>

Required

Explain Cody's error

<em>Cody made a mistake when calculating the slope of the line and this affected every other steps after than.</em>

See Proof

Slope (m) is calculated as thus:

$m =\frac{y_2 - y_1}{x_2 - x_1}$

$m =\frac{1 - 4}{\frac{2}{3} - \frac{1}{2}}$

$m =-\frac{ 3}{\frac{1}{6}}$

$m = -3/\frac{1}{6}$

$m = -3 * 6$

$m = -18$

This is in contrast to $m = -\frac{1}{2}$ , calculated by Cody

Solving further to determine the equation.

$y - y_1 = m(x - x_1)$

Where

$(x_1,y_1) = (\frac{1}{2},4)$

$m = -18$

$y - 4 = -18(x - \frac{1}{2})$

$y - 4 = -18x + 9$

Collect Like Terms

$y + 18x = 9 + 4$

$y + 18x = 13$

6 0

3 years ago

To compare two programs for training industrial workers to perform a skilled job, 20 workers are included in an experiment. Of t

nikklg [1K]

Answer:

$t=\frac{19.1-23.3}{\sqrt{\frac{4.818^2}{10}+\frac{5.559^2}{10}}}}=-1.805$

$p_v =P(t_{(18)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance

Step-by-step explanation:

Data given and notation

We can calculate the sample mean and deviation with these formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_{1}=19.1$ represent the mean for the sample mean for 1

$\bar X_{2}=23.3$ represent the mean for the sample mean for 2

$s_{1}=4.818$ represent the sample standard deviation for the sample 1

$s_{2}=5.559$ represent the sample standard deviation for the sample 2

$n_{1}=10$ sample size selected 1

$n_{2}=10$ sample size selected 2

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the average time taken when training under method 1 is less than the average time for Method 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1} \geq \mu_{2}$

Alternative hypothesis: $\mu_{1} < \mu_{2}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{19.1-23.3}{\sqrt{\frac{4.818^2}{10}+\frac{5.559^2}{10}}}}=-1.805$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=10+10-2=18$

Since is a one sided test the p value would be:

$p_v =P(t_{(18)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance

4 0

3 years ago

Brooklyn began her school day with 25 pieces of gum and gave x amount away. Amy

malfutka [58]

Answer:15

Step-by-step explanation:

3 0

3 years ago

Consider line A whose equation is y = -10x + 8. If line B is perpendicular to line A and has a y-intercept at y = 3, what is the

r-ruslan [8.4K]

Answer:

C) . y=(1/10)x+3