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mars1129 [50]
3 years ago
12

What is the answer to (14/5)/4​

Mathematics
1 answer:
Misha Larkins [42]3 years ago
8 0

14 / 5 = 2.8 / 4 = 0.7

Always divide what's in the bracket first.

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Usimov [2.4K]

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If two polygons are similar, their corresponding angles are the same, while corresponding sides are all in the same ratio.

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3 years ago
A bag contains 56 marbles: 7 red, green, 11 yellow, 17 brown, and 13 blue.
pav-90 [236]

Answer:

8/56

Step-by-step explanation:

Add up all other marble colors then find the difference from the total.

3 0
3 years ago
Read 2 more answers
PLEASE HELP I'm having trouble ​
Anastasy [175]

Answer:

c_{11}=56.1

c_{12}=12.1

c_{13}=236

Step-by-step explanation:

  • The product of two matrices X_{m\times{n}} and  Y_{n\times{r}} equals a matrix M_{m\times{r}}, where the first element of the subscript represents the amount of files of the matrix and the second element represents the amount of columns of the matrix.
  • Then, in this case  A_{1\times{3}}   B_{3\times{3}}, therefore, its product will result a matrix C_{1\times{3}}.
  • Because C matrix is going to have an only file and three columns, we now have to find the values of the elements in each column, based on the elements of A and B.
  • Commonly, to obtain the values of the resulting matrix, we just have to multiply each file of the first matrix by each column of the second matrix and sum, as follows:
  1. c_{11}=77\times1.2+39\times2.2-33\times3.7=56.1
  2. c_{12}=77\times1.4+39\times1.1-33\times4.2=12.1
  3. c_{13}=77\times3.1+39\times5.6-33\times6.7=236
  • Finally, C matrix is \begin{pmatrix}\56.1 & 12.1& 236\end{pmatrix}
4 0
3 years ago
Travel time data is collected on an arterial. With 30 runs, an average travel time of 152 seconds is computed over the 2.0 miles
o-na [289]

Answer:

a

 The 95% confidence bounds is  145.80 <  \mu <   158.19

b

It was not necessary to make any assumption about the shape of the travel  time distribution

Step-by-step explanation:

From the question we are told that

 The sample size is  n =  30  

  The sample mean  is  \=x = 152

   The standard deviation is  \sigma =  17.3 \  second

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =  1.96 *  \frac{17.3 }{\sqrt{30} }

=>     E = 6.19  

Generally 95% confidence bounds  is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=>  152  -6.19 <  \mu <  152  -6.19

=> 145.80 <  \mu <   158.19

This 95% confidence bounds show that there is 95% confidence that the true mean lies within this bound hence there is it was not necessary to make any assumption about the shape of the travel  time distribution

5 0
3 years ago
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