Answer:
1. (a-c)
+ b
2. 9m + 2
3. 6a
4. (5a - 3b)
Step-by-step explanation:
1. since a and c share the same squareroot x, you can combine these together.
2. First add like terms together. 4m - m + 6m = 9m. Then 5
and -3
combined equals 2
3. First simplify the square roots. squareroot of 16 is 4. square root of 49 is 7. square root of 81 is 9. They are all multiplied by a in the expression. Thus 4a - 7a + 9a = 6a
4. First simplify the radicals, they are not perfect. square root of 125 is equivalent to sqrt(25 * 5), which sqrt of 25 is 5, but we keep the sqrt of 5. For sqrt of 45, it is the same as sqrt9 * sqrt5. sqrt of 9 is the same as 3 and we keep sqrt 5. Thus we get the below:
5a
- 3b
We can combine the two like terms and get the final answer above.
please give thanks by clicking the heart :)
2x² - 3xy
2(1)² - 3(1)(2)
2(1) - 3(2)
2 - 6
-4
<h2>
Answer:</h2>
By process of elimination, we can eliminate:
- <em>A:</em> <em>y = 3x - 1</em>
- <em>C: y = 3x + 1</em>
- <em>B: y = -3x</em>
<em>A and C</em> don't work because the given line has it's y-intercept at the origin, therefore, no y-intercept is written. <em>B </em>is not it either because the line <em>does not</em> go <em>down</em> from <em>left to right</em>, therefore, the slope is <em>not</em> negative.
The answer is <em>D: y = 3x</em> because since the line goes <em>up</em> from <em>left to right</em>, the slope is positive, and the y-intercept is the origin, so the equation will have no b.
Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.
1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.
According to this theorem,

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

Take positive value x. You get

2. According to the previous theorem,

Then

Answer: 
This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

This means that you cannot find solutions of this equation. Then CD≠2 cm.
Rewrite the rational (fraction) exponents using the formula ^n<span>√a^x= a x/n
3m 1/2 </span>