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stellarik [79]
2 years ago
12

Replace the values of m and n to show the solutions of this equation. x^2 + 6x - 5 = 0

Mathematics
2 answers:
soldi70 [24.7K]2 years ago
6 0

Answer: x = 2, x = 3 ( whichever is m and whichever is n )

Step-by-step explanation: h

x^2 + 6x - 5 = 0

( x - 2 ) ( x - 3 ) you take the x^2 and you split it into separate groups

the negatives will give you a positive 6, but also a negative 5. you want to use multiples of 6 to add up to -5. so you do ( x - 2 ) and ( x - 3 ) and it doesn't matter what order you do the numbers!! both are negative trying to add up to a negative.

then you want to get x.

x - 2 = 0

add two to the 0 and x = 2

then the other x

x - 3 = 0

add the three to the 0 and x = 3

HACTEHA [7]2 years ago
4 0

Answer:

I really hope someone answers this soon bc i need it too!!

Step-by-step explanation:

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The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the
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Answer:

Brand 1    Brand 2    Difference

37734       35202        2532

45299      41635         3664

36240      35500        740

32100      31950         150

37210       38015       −805

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38200    37810          390

33500    33215        285

Sum of difference = 2532+ 3664+740+150 −805+  560 +390 +285 = 7516

Mean = d=\frac{7516}{8}

Mean = d=939.5

a) d= 939.5

\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}

=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, t_{\frac{\alpha}{2}}=3.499

Formula for confidence interval = \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)

Substitute the values

confidence interval = 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

confidence interval = 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right) to  = 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

Confidence interval −843.396\ to  2722.396

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