Answer: Option D. 1,778
Solution:
Standard brick:
Width: w=3.625 in
Height: h=2.25 in
Length: l=7.625 in
Volumen of one standard brick: v
v=w*h*l
v=(3.625 in)*(2.25 in)*(7.625 in)
v=62.19140625 in^3
Pallet of bricks:
Side: s=4 feet
s=(4 feet)*(12 in / 1 feet)→s=48 in
Volume of a pallet of bricks: V=s^3
V=(48 in)^3
V=110,592 in^3
Number of bricks could be in a pallet: n
n=V/v
n=(110,592 in^3) / (62.19140625 in^3)
n=1,778.252119
n=1,778
4x^2-25= (2x)^2-5^2=(2x-5)(2x+5)
Used: a^2-b^2=(a+b)(a-b)
The top of “^” needs a number to solve it.
It’s the second one for number #5 . hope this helps
