from a vertical cliff 80 m above sea level a fishing boat is observed at an angle of depression of 6 degrees . how far out to se
a is the boat?
1 answer:
Answer:
The boat is 8.4m out of the sea
Step-by-step explanation:
Kindly find attached rough sketch of the problem.
From the sketch we can see that the observer from the cliff and the horizontal distance forms a right angle triangle
Let the horizontal distance be x
Let the angle of elevation from the boat be y
Applying sum of angles in a triangle
90+6+y= 180
96+y=180
y=180-96
y= 84°
Applying SOH CAH TOA
Using TOA
Tanθ= opposite /adjacent
Tan 84= 80/x
x= 80/tan 84
x= 80/9.51
x= 8.4m
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