Answer:
For question 3, you would just add 2 to the x values and subtract 2 from the y values, so it would be:
J' (-2, 5)
K' (2, 6)
L' (1, 2)
M' (-3, 1)
For question 4 you would subtract 7 from the x values and 6 from the y values, and that would be:
W' (-6, 1)
X' (-1, -1)
Y' (-3, -6)
Z' (-8, -4)
For question 9 you would end up with:
X' (6, -5)
Y' (7, 1)
Z' (4, 0)
For question 10 you would end up with:
Q' (-1, 2)
R' (1, 7)
S' (-2, 6)
T' (-4, 1)
For question 11 you would end up with:
L' (4, 1)
M' (8, 5)
N' (6, 7)
P' (2, 3)
For question 12 you would end up with:
G' (6, -7)
H' (6, -4)
I' (1, -7)
Hope this is what you were looking for!
Step-by-step explanation:
Answer: 1 9/15
Step-by-step explanation:
I can’t speak Spanish
Hope this will help u..............
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b) It is a cubic function of 4 terms.
- In this case p(3) = t + 2 is synonymous for p = 3 + 2. Remember p is synonymous for y. So in this equation it is p = 5.
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Hope this helps!
Answer: The first number that appears in both sequences is 28.
Step-by-step explanation:
Let's write down numbers from each of the sequences
Sequence 1) We need to start from 7 and multiply 4
7x4=28, 28x4=112
The sequence is 7,28,112...
Sequence 2) We need to start from 8 and add 5
5+8=13, 13+5=18, 18+5=23, 23+5=28
The sequence is 8,13,18,23,28...
They both have 28