Ugh Once again I need help please help!
2 answers:
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The Fundamental Theorem of Calculus regarding geometry states that
Where F is the indefinite integral of
The first step is to integrate
Then substitute the value of
and 
into 
![[2 (b)^{2}]-[2 (1)^{2}] = 240](https://tex.z-dn.net/?f=%5B2%20%28b%29%5E%7B2%7D%5D-%5B2%20%281%29%5E%7B2%7D%5D%20%3D%20240%20)
Hence the limit of the area under is between and
Where F is the indefinite integral of
The first step is to integrate
Then substitute the value of
Hence the limit of the area under
Answer:
Step-by-step explanation:
<h3><u>Question 6</u></h3>To find the greatest common factor (GCF), first list the prime factors of each number:
- 42 = 2 × 3 × 7
- 60 = 2 × 2 × 3 × 5
42 and 60 share one 2 and one 3 in common.
Multiply them together to get the GCF: 2 × 3 = 6.
Therefore, 6 is the GCF of 42 and 60.
Divide the numerator and the denominator by the found GCF:
To find the greatest common factor (GCF), first list the prime factors of each number:
- 80 = 2 × 2 × 2 × 2 × 5
- 272 = 2 × 2 × 2 × 2 × 17
80 and 272 share four 2s in common.
Multiply them together to get the GCF: 2 × 2 × 2 × 2 = 16.
Therefore, 16 is the GCF of 80 and 272.
Divide the numerator and the denominator by the found GCF: