Consider the equation 2 (5x-4) = ax +b find the value for a and value for b so that the equation has only one solution explain y
1 answer:
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Translate the info given into equations:
<span>A positive integer is 15 less than another -----> x = y - 15
</span><span>If 4 times the reciprocal of the smaller integer is subtracted from the reciprocal of the larger integer, then the result is − 3/4
</span>------> (1/y) - (4/x) = -3/4
Use substitution, replace 'x' with 'y-15' in 2nd equation
We know that both x and y must be positive integers, so y =-1 is not a solution.
If y=20, then x = 20-15 = 5
Final answer:
The pair of integers is (5,20)
<span>A positive integer is 15 less than another -----> x = y - 15
</span><span>If 4 times the reciprocal of the smaller integer is subtracted from the reciprocal of the larger integer, then the result is − 3/4
</span>------> (1/y) - (4/x) = -3/4
Use substitution, replace 'x' with 'y-15' in 2nd equation
We know that both x and y must be positive integers, so y =-1 is not a solution.
If y=20, then x = 20-15 = 5
Final answer:
The pair of integers is (5,20)