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zzz [600]
3 years ago
7

What's the solution for 2x 7y=2 x y=-1

Mathematics
1 answer:
Lerok [7]3 years ago
5 0
<span>Simplifying

(2x + -7y ) = 0

Multiply
(2x + -7y) * (x + y) </span><span>
(2x * (x + y) + -7y * (</span><span>x + y)) = 0
</span>((x * 2x + y * 2x) + -7y * (x + y)) = 0<span>

</span>Reorder the terms:
((2xy + 2x2) + -7y * (x + y)) = 0
((2xy + 2x2) + -7y * (x + y)) = 0
(2xy + 2x2 + (x * -7y + y * -7y)) = 0
(2xy + 2x2 + (-7xy + -7y2)) = 0<span>

Reorder the terms:
(2xy + -7xy + 2x2 + -7y2) = 0
</span>
<span>Combine like terms: 2xy + -7xy = -5xy
(-5xy + 2x2 + -7y2) = 0

</span>Solving -5xy + 2x2 + -7y2 = 0<span>

Solving for variable 'x'.

Factor a trinomial. 
(2x + -7y)(x + y) = 0
</span>



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7 bolas

Step-by-step explanation:

Aquí, queremos saber el número de bolas que se deben sacar para estar seguros de haber extraído al menos dos bolas del mismo color.

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3 years ago
Due tonight please help me
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k=61, l=61, m58

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5 0
3 years ago
Someone, please help. Will Mark brainlist if the answer is correct.<br><br> Screenshot it below.
pav-90 [236]

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (x-9)^2+y^2=4\implies (x-\stackrel{h}{9})^2+(y-\stackrel{k}{0})^2=2^2~\hfill \stackrel{center}{(9,0)} \\\\\\ (x-\stackrel{h}{3})^2+(y-\stackrel{k}{2})^2=4\implies (x-\stackrel{h}{3})^2+(y-\stackrel{k}{2})^2=2^2~\hfill \stackrel{center}{(3,2)}

Check the picture below.

well, its radius didn't change, anyhow, you know what to check out.

7 0
3 years ago
Read 2 more answers
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