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ValentinkaMS [17]
3 years ago
8

By how much does a3 - 2a exceed a2 + a - 6?

Mathematics
2 answers:
laiz [17]3 years ago
8 0
a^3-2a-(a^2+a-6)=a^3-2a-a^2-a+6=a^3-a^2-3a+6
Kaylis [27]3 years ago
6 0
Hello,

Let's d the exceed number.

d=a^3-2a-(a²+a-6)=a^3-2a-a²-a+6=a^3-a²-3a+6

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Help. I need help with these questions ( see image).<br> Please show workings.
Andrew [12]

9514 1404 393

Answer:

  4)  6x

  5)  2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

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where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the <em>power rule</em>.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

  lim[h→0](f(x+h)-f(x))/h = 2ax +b

__

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

3 0
3 years ago
I need help on a equation −4a5⋅6a5​
Pavel [41]
I don’t understand the equation but you can use Photomath to solve any equation you need to solve. It’s and app for free.
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3 years ago
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elena55 [62]
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8 0
3 years ago
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Write the expression 5x+2x^2-7+2x^3
avanturin [10]

2x^3+2x^2+5x-7, That would be the answer.

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3 years ago
(-x+4/4)+(-x+2/4) what’s the answer?
ss7ja [257]

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Step-by-step explanation:

Simplify the expression.

3 0
3 years ago
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