3 years ago

By how much does a3 - 2a exceed a2 + a - 6?

Mathematics

2 answers:

laiz [17]3 years ago

8 0

$a^3-2a-(a^2+a-6)=a^3-2a-a^2-a+6=a^3-a^2-3a+6$

Kaylis [27]3 years ago

6 0

Hello,

Let's d the exceed number.

d=a^3-2a-(a²+a-6)=a^3-2a-a²-a+6=a^3-a²-3a+6

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