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Anton [14]
3 years ago
6

The graph shows the temperature of ice cream in an ice chest during an overnight trip. What is the domain of this function?

Mathematics
2 answers:
svet-max [94.6K]3 years ago
6 0
Domain is the set of x-values on a graph.
In the given graph,the values starts from zero and ends at 30.
Therefore,
<span>The domain is all real numbers 0 through 30.</span>
mariarad [96]3 years ago
4 0

Let

x-------> the number of hours

y------> the temperature in degrees Fahrenheit

we know that

For x=0\ hours

y=-10\°\ F

For x=30\ hours

y=30\°\ F

The domain of the function is the interval----------> [0,30]

0\ hours \leq x\leq 30\ hours

The range of the function is the interval----------> [-10,30]

-10\°\ F \leq y\leq 30\°\ F

therefore

<u>the answer is</u>

The domain is all real numbers 0 through 30

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A cylindrical candle has a volume of approximately 400cm^3 and is 8 cm tall. What is the radius of the candle?
katrin2010 [14]

Answer:

<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>

We know that

V = πr²h

400 = 22/7 × r² × 8

400 × 7 = 22 × 7r²

2800 = 154r²

2800/154 = r²

18 ≈ r²

4.2 = r

6 0
3 years ago
Read 2 more answers
Find the value of x. If necessary, round to the nearest tenth.
Oksi-84 [34.3K]

Answer:

the answer is 7 i believe

4 0
2 years ago
PLEASE HELP!! NO LINKS!!
dlinn [17]

Answer:

42.1 cm

Step-by-step explanation:

θ = 265°

Radius (r) = 9.1 cm

Arc length of major arc GH = θ/360 × 2πr

Plug in the values into the equation

Length of arc GH = 265/360 × 2 × π × 9.1

= 42.0886149

= 42.1 cm (nearest tenth)

6 0
3 years ago
Can anyone help me? <br><br> a^2 -2a+2a-4-a^2+2a+3a+6=3a+9
Alinara [238K]

Answer:

a=7/2

Step-by-step explanation:

a^2-2a+2a-4-a^2+2a+3a+6=3a+9

You want to solve for "a"

1. Mover all terms on the right side to the left side setting this equation to zero.

2. Combine Like Terms

3. Divide to isolate your "a"

6 0
3 years ago
Read 2 more answers
Solve for x<br> Urgent need help
fiasKO [112]
I believe you need to solve this using the quadratic formula!
To begin, this is what it is:
x= -b ± <span>√ b^2 - 4ac / 2a
Just plug in what you have in your problem...
2 being a, 13 being b, and -24 being c.
So we get:
x= -13 </span>± <span>√13^2 - 4(2)(-24) / 2(2)
x= -13 </span><span>± √169 - 8 (-24) / 4</span>
<span>x= -13 <span>± √169 + 192 / 4</span>
x= -13 </span>± √<span>361 / 4
The square root of 361 is 19.
So you have: -13 </span><span>± 19 / 4.
Here's where you take the equation </span>-13 <span>± 19 and put the addition and subtraction sign to use.
-13 - 19 = -32
and
-13 + 19 = 6
Now all is left to do is divide the two numbers by 4.
-32/4 = -8
and
6/4 = 3/2

x = -8, 3/2</span>
6 0
4 years ago
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