According to the Central Limit Theorem, the distribution of the sample means is approximately normal, with the mean equal to the population mean (1.4 flaws per square yard) and standard deviation given by:

The z-score for 1.5 flaws per square yard is:

The cumulative probability for a z-score of 1.11 is 0.8665. Therefore the probability that the mean number of flaws exceeds 1.5 per square yard is
1 - 0.8665 = 0.1335.
Answer:
The number of heads observed is 121.14 heads
Step-by-step explanation:
The formula for the z-score of a proportion is given as follows;

Where:
= Sample proportion
p = Population success proportion = 0.5
q = 1 - p = 1 - 0.5 = 0.5
n = Number in of observation = 200
z = 2.99
Hence, we have;

Therefore;

= 0.6057

∴ The number of heads observed = 200 × 0.6057 = 121.14 heads.
Greatest to least is 3 1/2 , 3 , 1/3 , 0.3 , 0.03
Hope im right
B) False
Because the negation makes it opposite of what is was.