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Andreas93 [3]
3 years ago
15

Geometry question please help, any help is appreciated!

Mathematics
1 answer:
raketka [301]3 years ago
6 0
Equation of the circle is
(x-h)² + (y-k)² = r²,

where (h, k) are coordinates of the center of the circle.
(h,k)= (0,-2)
radius r= 6

(x-0)² +(y-(-2))²=6²

x² + (y+2)² = 36
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Laura went to a golf shop that has a golf simulator. The simulator estimates the distance that each ball she hits would have gon
Alex_Xolod [135]

Answer:

I can only help you with Part C and E as these two are the ones I am able to answer.

Part C: slopes are not the same

Part E:  195 yards

Step-by-step explanation:

Part C:

Part E: The slope of the line follows a linear pattern; therefore, find the equation for the line by calculating the slope and plugging in a point.

Slope:

y2-y1/x2-x1; (9, 105) (8,115)

(115-105)/(8-9) = -10; the slope is -10, now solve for the equation of the line.

y=mx+b; plug in the point (9,105)

105 = -10(9) +b

105 = -90 +b, add 90 to both sides

195 = b; rewrite the equation;

y=-10x+195; x stands for the iron, plug in 0 for x;

y=-10(0)+195

y=195 yards.

7 0
3 years ago
I need some help find the area of the shaded region and round to the nearest hundredth
exis [7]

Answer:

The area of the shaded region is 21.45cm².

5 0
3 years ago
F(x) = x². What is g(x)?<br> A.g(x)=(1/3x)^2<br> B:g(x)=1/3x^2<br> C:g(x)=1/9x^2<br> D:g(x)=3x^2
lana [24]

Answer:

B

Step-by-step explanation:

We know that 3² = 9, so for g(x) to pass through (3,3), we need to multiply x² by 1/3, giving option B.

8 0
2 years ago
What is the value of x6+y2 when x equals 1 and y equals 11
Kazeer [188]

Answer:

28

Step-by-step explanation:

x equals 1

y equals 11

you would plug the numbers in

(1)6 plus (11)2 which if you multiply them

6 plus 22 would give you 28

6 0
3 years ago
Twice the greater of two consecutive odd intergers is 13 less than three times the lesser. Find the intergers ​
erastova [34]

Answer:

\large\boxed{15, 16}

Step-by-step explanation:

2 consecutive integers represented as variables:

x, x + 1

Greater one: x + 1

Lesser one: x

Write as an equation

2(Greater) + 13 = 3(Lesser)

Substitute in known values

2(x + 1) + 13 = 3(x)

Multiply

2x + 2 + 13 = 3x

Subtract 2x from both sides of the equation

2 + 13 = x

Add 2 + 13 to simplify

x = 15

Lesser = x = 15

Greater = x + 1 = 15 + 1 = 16

\large\boxed{15, 16}

Hope this helps :)

3 0
3 years ago
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