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3 years ago

Story problems with intergers

Mathematics

1 answer:

mr Goodwill [35]3 years ago

3 0

Ok so for 17:
You would use Balance=Credit-Debit.
Plug the numbers in
Balance=84-29
84-29= 55
55 would be your balance.
18:
If the freezing point was 32F then when Tim added the potassium it went DOWN 3 degrees what would it be?
Well subtract 32 and 3!
32-3=29
29 would be your answer.
19:
If the citys budget is 8,000,000 but they spend 12,000,000 that means they spend an extra 4,000,000 a year.
If i'm correct 4,000,000 would be your answer.

Hope this helped!

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Use synthetic division to find the quotient and remainder. Express your answer as a polynomial.

OLEGan [10]

1. 2x³ - 11x² + 13x - 21 ÷ x - 3

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3 | 2 -11 13 -21

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*************************************************************

2. 3x³ + 7x² - 13x + 10 ÷ x + 2

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3. 2x³ + 13x² - 21x + 9 ÷ x - 1

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2 15 -6 3

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3 years ago

Suppose a sample of 80 with a sample proportion of 0.58 is taken from a

Anvisha [2.4K]

Answer:

99.7% confidence interval is $[0.4162,0.7437]$

Step-by-step explanation:

The formula for a confidence interval for a population proportion is $CI=\hat{p}\pm z^*\sqrt{\frac{\hat{p}(1-\hat{p})}{n} }$ where $\hat{p}$ is the sample proportion, $n$ is the sample size, and $z^*$ is the critical score for the desired confidence level.

We are given a sample size of $n=80$ and a sample proportion of $\hat{p}=0.58$ . Our critical score for a 99.7% confidence level would be $z^*=normalcdf(0.9985,0,1)=2.9677$

Therefore, the approximate 99.7% confidence interval for the population parameter is $CI=\hat{p}\pm z^*\sqrt{\frac{\hat{p}(1-\hat{p})}{n} }=0.58\pm 2.9677\sqrt{\frac{0.58(1-0.58)}{80} }=[0.4162,0.7438]$

So we are 99.7% confident that the true population proportion is contained within the interval $[0.4162,0.7437]$

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