1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gnoma [55]
3 years ago
8

Lella will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $46 and costs an ad

ditional $0.14 per mile driven. The
second plan has an initial fee of $51 and costs an additional $0.10 per mile driven

Mathematics
1 answer:
Helen [10]3 years ago
6 0
The plans cost the same at 125 miles. the cost is $63.50
You might be interested in
A newspaper ad includes a telephone number 1-555-dial vsw. How many seven letter arrangements are possible for the phone number
trapecia [35]
Let u be the set of all words containing 7 letters(26 letters to the power 7)
7 0
3 years ago
I need some help please
gizmo_the_mogwai [7]

Answer:

a) -10

b) 7

Step-by-step explanation:

a) 2(x + 3) = x - 4

=  > 2x + 6 = x - 4

=  > 2x - x =  - 4 - 6

=  > x =  - 10

b) 4(5x - 2) = 2(9x + 3)

=  > 20x -8 = 18x + 6

=  > 20x - 18x = 8 + 6

=  > 2x = 14

=  > x =  \frac{14}{2}  = 7

3 0
3 years ago
Read 2 more answers
For x, y ∈ R we write x ∼ y if x − y is an integer. a) Show that ∼ is an equivalence relation on R. b) Show that the set [0, 1)
vodomira [7]

Answer:

A. It is an equivalence relation on R

B. In fact, the set [0,1) is a set of representatives

Step-by-step explanation:

A. The definition of an equivalence relation demands 3 things:

  • The relation being reflexive (∀a∈R, a∼a)
  • The relation being symmetric (∀a,b∈R, a∼b⇒b∼a)
  • The relation being transitive (∀a,b,c∈R, a∼b^b∼c⇒a∼c)

And the relation ∼ fills every condition.

∼ is Reflexive:

Let a ∈ R

it´s known that a-a=0 and because 0 is an integer

a∼a, ∀a ∈ R.

∼ is Reflexive by definition

∼ is Symmetric:

Let a,b ∈ R and suppose a∼b

a∼b ⇒ a-b=k, k ∈ Z

b-a=-k, -k ∈ Z

b∼a, ∀a,b ∈ R

∼ is Symmetric by definition

∼ is Transitive:

Let a,b,c ∈ R and suppose a∼b and b∼c

a-b=k and b-c=l, with k,l ∈ Z

(a-b)+(b-c)=k+l

a-c=k+l with k+l ∈ Z

a∼c, ∀a,b,c ∈ R

∼ is Transitive by definition

We´ve shown that ∼ is an equivalence relation on R.

B. Now we have to show that there´s a bijection from [0,1) to the set of all equivalence classes (C) in the relation ∼.

Let F: [0,1) ⇒ C a function that goes as follows: F(x)=[x] where [x] is the class of x.

Now we have to prove that this function F is injective (∀x,y∈[0,1), F(x)=F(y) ⇒ x=y) and surjective (∀b∈C, Exist x such that F(x)=b):

F is injective:

let x,y ∈ [0,1) and suppose F(x)=F(y)

[x]=[y]

x ∈ [y]

x-y=k, k ∈ Z

x=k+y

because x,y ∈ [0,1), then k must be 0. If it isn´t, then x ∉ [0,1) and then we would have a contradiction

x=y, ∀x,y ∈ [0,1)

F is injective by definition

F is surjective:

Let b ∈ R, let´s find x such as x ∈ [0,1) and F(x)=[b]

Let c=║b║, in other words the whole part of b (c ∈ Z)

Set r as b-c (let r be the decimal part of b)

r=b-c and r ∈ [0,1)

Let´s show that r∼b

r=b-c ⇒ c=b-r and because c ∈ Z

r∼b

[r]=[b]

F(r)=[b]

∼ is surjective

Then F maps [0,1) into C, i.e [0,1) is a set of representatives for the set of the equivalence classes.

4 0
3 years ago
Is -12/6 a rational number?
stiv31 [10]
A rational number is any number that can be turned into a fraction....it can be negative or positive.

Therefore, -12/6 is a rational number
3 0
3 years ago
So, I need some help with these scatter plot questions. (basically free points because these might be easy for you!) (20 points)
nlexa [21]

Hello,

I have a graphing calculator so this will be easy for me to answer and explain how to figure these out. Here we go!

1. Well on a Ti - 84 plus calculator it says graph then you put in thee equations for each and C and D are already incorrect cause they go straight up and B is incorrect because it is a straight line on the top going straight. In this case your looking for a line that goes through the dots. And the answer would be A) Y = 1/2x + 7.

2. B) Then umber of accidents were reduced by 0.67 per month for every additional driver in the program.

3. Key: Y means yes N means no. Plot A had 1 disease present and 2 not present. Plot B has 3 diseases present and 1 disease not present.

4. Category A had 36 groups in group 1. and Category B had 12 groups in group 1. Easy!

Please mark Brainliest!

Hope I Helped!

Have a fantastic Day!


3 0
3 years ago
Other questions:
  • PLEASE HELP ME FAST BRAINLIEST TO FIRST PERSON TO ANSWER CORRECTLY WITH EXPLONATION!!
    12·2 answers
  • A diver jumps from a diving board that is 24 feet above the water. The height of the diver is given by: h= -16 ( t - 1.5 ) ( t +
    6·2 answers
  • Which word phrase represents the variable expression? 2(n + 4) 
    15·1 answer
  • How do i determine the dimensions of a rectangle
    9·1 answer
  • Please help me, I really need solve this.
    6·1 answer
  • (Please Help!) Find the radius of a circle so that its area and circumference have the same value.
    14·1 answer
  • The mean annual premium for automobile insurance in the United States is $1,499. Being from Pennsylvania, you believe automobile
    13·1 answer
  • Help pleaseee guysss
    7·1 answer
  • Express de Number 80,000 in scientific notation ❤️
    14·2 answers
  • AB has endpoints A(-9, 14) and B(21,5). Find the coordinates of midpoint M.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!