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Vedmedyk [2.9K]
3 years ago
11

An airplane has an air speed of 520 mph with a heading of 215 degrees. Find the plane's ground speed and course if it encounters

the following winds.
A.) A headwind of 32 mph.

B.) A tailwind of 32 mph.
Mathematics
1 answer:
a_sh-v [17]3 years ago
5 0
<span>Assuming east is positive x, north is positive y, break down the airplane's velocity into a vector in the x-y plane.
The plane is traveling 340 mph at a bearing of 210 degrees or (340cos(210), 340 sin(210)).
The wind is blowing from the west (to the east) at 50 mph or (50,0).
The actual ground speed would be the vector sum of those two (340 cos(210)+50, 340 sin(210)) or (-294.4+50,-170) or (-244.4,-170).
The magnitude of that velocity vector is




For direction



Since this angle is measured from the (-y) axis, we add 180 to get the actual heading.
The plane is traveling at 297.8 mph at a heading of 214.8 degrees. </span>

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GaryK [48]

The equation that show the relationship between Anna earning and time worked is y = 8.5h.

<h3>Linear equation</h3>

Linear equation is in the form:

y = mx + b

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Let y represent Anna earnings for working h hours.

Since she charges $8.50 per hour to babysit. Hence:

y = 8.5h

The equation that show the relationship between Anna earning and time worked is y = 8.5h.

Find out more on Linear equation at: brainly.com/question/14323743

6 0
3 years ago
What is 2.346 as a percent
34kurt

Answer:

Step-by-step explanation:

to turn a decimal to a percent, multiply by 100.....or if there is a decimal in there, start from the decimal and just move 2 spaces to the right.

2.346 = 234.6%

and just so you know, to turn a percent to a decimal, divide by 100...or move the decimal point 2 spaces to the left

6 0
3 years ago
Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k
ch4aika [34]

Given

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the curl of \vec v is

\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

7 0
3 years ago
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Answer:

19,500 - (1,000 x 12) = X

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Step-by-step explanation:

Given that Brianna earns $ 19,500 per year and Lisa earns $ 1,000 per month, to write a numerical expression that represents how much more Brianna earns per year than Lisa the following calculations and equations must be performed:

19,500 - (1,000 x 12) = X

19,500 - 12,000 = X

7,500 = X

Thus, Brianna earns $ 7,500 more than Lisa throughout the year.

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Answer:

{-5,-4,2,4}

Step-by-step explanation:

the domain is which x-values are included so use each of the x-values for each pair. Make sure if there are reapeats that you only write them once.

3 0
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