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Vedmedyk [2.9K]
3 years ago
11

An airplane has an air speed of 520 mph with a heading of 215 degrees. Find the plane's ground speed and course if it encounters

the following winds.
A.) A headwind of 32 mph.

B.) A tailwind of 32 mph.
Mathematics
1 answer:
a_sh-v [17]3 years ago
5 0
<span>Assuming east is positive x, north is positive y, break down the airplane's velocity into a vector in the x-y plane.
The plane is traveling 340 mph at a bearing of 210 degrees or (340cos(210), 340 sin(210)).
The wind is blowing from the west (to the east) at 50 mph or (50,0).
The actual ground speed would be the vector sum of those two (340 cos(210)+50, 340 sin(210)) or (-294.4+50,-170) or (-244.4,-170).
The magnitude of that velocity vector is




For direction



Since this angle is measured from the (-y) axis, we add 180 to get the actual heading.
The plane is traveling at 297.8 mph at a heading of 214.8 degrees. </span>

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Answer:

0.813

0.500

Step-by-step explanation:

Use binomial probability.

P = nCr p^r q^(n−r)

where n is the number of trials,

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p is the probability of success,

and q is the probability of failure (1−p).

In this problem, n = 5, p = 0.5, and q = 0.5.

"At least 2 girls" means r = 2, 3, 4, or 5.

Or, we can use the complement.

P(at least 2 girls) = 1 − P(at most 1 girl)

P(at least 2 girls) = 1 − P(r=0 or r=1)

P(at least 2 girls) = 1 − ₅C₁ (0.5)¹ (0.5)⁵⁻¹ − ₅C₀ (0.5)⁰ (0.5)⁵⁻⁰

P(at least 2 girls) = 1 − 5 (0.5) (0.5)⁴ − 1 (1) (0.5)⁵

P(at least 2 girls) = 1 − 6 (0.5)⁵

P(at least 2 girls) ≈ 0.813

"At most 2 girls" means r = 0, 1, or 2.

P(at most 2 girls) = P(r=0, r=1, or r=2)

P(at most 2 girls) = ₅C₀ (0.5)⁰ (0.5)⁵⁻⁰ + ₅C₁ (0.5)¹ (0.5)⁵⁻¹ + ₅C₂ (0.5)² (0.5)⁵⁻²

P(at most 2 girls) = 1 (1) (0.5)⁵ + 5 (0.5) (0.5)⁴ + 10 (0.5)² (0.5)³

P(at most 2 girls) = 16 (0.5)⁵

P(at most 2 girls) = 0.500

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Step-by-step explanation:

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Step-by-step explanation:

<h3>hope it helps</h3>
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