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3 years ago

Plzzz hellppp URGENTLY !!!!!!5,000 rounded to the nearest hundred.

Mathematics

2 answers:

irina [24]3 years ago

5 0

5000 rounded to the nearest hundredth is 5000

yaroslaw [1]3 years ago

3 0

5,000 has no decimals therefore it would be 5,000

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What is the basic unit for length in the si unit

klio [65]

Answer: i think its metre

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3 years ago

Usmg Cire SOIULIONI LU a LILETAI Equatre

natulia [17]

Answer:

5 – 6x = 8x + 17

⇔ 5 - 17 = 8x + 6x

⇔ -12 = 14x

⇔ x = -6/7

Step-by-step explanation:

7 0

3 years ago

An oblique cone has a radius of 4 units, a height of 8.5 units, and a slant length of 11.7 inches. What is the volume of the obl

trasher [3.6K]

Oblique Cone

The volume of the oblique cone is 144.49 cubic inches , if an oblique cone has a radius of 4 units, a height of 8.5 units, and a slant length of 11.7 inches.

Step-by-step explanation:

An oblique cone has a radius of 4 units

A height of 8.5 units

A slant length of 11.7 inches

We have to use the slant height to calculate actual base

So in a right angle triangle when two sides are given the third side is calculated by

Root (sqr(11,7) - sqr(8.5)) = 8.03 units

$\sqrt{11.7^{2} - 8.5^{2} }$

⇒ 8.03 units

Formula to calculate the volume of oblique cone,......................(1)

V = $\frac{1}{3} bh$

If r is the distance of the base of the height from the center of the circle [ this is because the base of the height is outside the oblique cone]

V = $\frac{1}{3} \pi r^{2} h$

Where r is the distance if the base of the height from the center of the circle [ this is because the base of the height is outside the oblique cone]

Here r = 8.03 - 4 = 4.03 units

Volume = $\frac{1}{3}$ × 3.14 × 4.03 × 4.03 × 8.5

Volume = 144.49 cubic inches

Hence, the volume of the oblique cone is 144.49 cubic inches , if an oblique cone has a radius of 4 units, a height of 8.5 units, and a slant length of 11.7 inches.

6 0

3 years ago

Read 2 more answers

A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday�s mail. In actuali

Softa [21]

Answer:

P(Y = 0) = 0.09

P(Y = 1) = 0.4

P(Y = 2) = 0.32

P(Y = 3) = 0.19

Step-by-step explanation:

Let the events be:

$W =$ Wednesday

$T =$ Thursday

$F =$ Friday

$S =$ Saturday

Their corresponding probabilities are

$P(W) = 0.3\\P(T) = 0.4\\P(F) = 0.2\\P(S) = 0.1$

Since $Y$ = number of days beyond Wednesday that it takes for both magazines to arrive(so possible $Y$ values are 0, 1, 2 or 3)

The possible number of outcomes are therefore $4^2 = 16\\(W, W), (W, T), (W, F), (W, S)\\(T, W), (T, T), (T, F), (T, S)\\(F, W), (F, T), (F, F), (F, S)\\(S, W), (S, T), (S, F), (S, S)$

The values associated for each of the outcomes are as follows:

$Y(W, W) = 0, Y(W, T) = 1, Y(W, F) = 2, Y(W, S) = 3\\Y(T, W) = 1, Y(T, T) = 1, Y(T, F) = 2, Y(T, S) = 3\\Y(F, W) = 2, Y(F, T) = 2, Y(F, F) = 2, Y(F, S) = 3\\Y(S, W) = 3, Y(S, T) = 3, Y(S, F) = 3, Y(S, S) = 3$

The probability mass function of $Y$ is,

$P(Y = 0) = 0.3(0.3) = 0.09\\P(Y = 1) = P[(W, T) or (T, W) or (T, T)]\\= [0.3(0.4) + 0.3(0.4) + 0.4(0.4)]\\= 0.4\\\\P(Y = 2) = P[(W, F) or (T, F) or (F, W) or (F, T) or (F, F)]\\= [0.3(0.2) + 0.4(0.2) + 0.2(0.3) + 0.2(0.4) + 0.2(0.2)]\\= 0.32\\\\P(Y = 3) = P[(W, S) or (T, S) or (F, S) or (S, W) or (S, T) or (S, F) or (S, S)]\\= [0.3(0.1) + 0.4(0.1) + 0.2(0.1) + 0.1(0.3) 0.1(0.4) + 0.1(0.2) + 0.1(0.1)]\\= 0.19$

7 0

3 years ago

I just need answers to the odd numbered questions.<br> I would appreciate the help<br><br> 35 points

Misha Larkins [42]

Answer:

Step-by-step explanation:

Combine real terms and combine complex terms

1) 3 + 2i + 2 - 5i = 3 +2 + 2i - 5i

= 5 + (2-5)i

= 5 + (-3)i

= 5 - 3i

3) 2 - (1 - 2i) + (4 -5i ) - (1 - 3i) = 2 -1 + 2i + 4 - 5i - 1 + 3i

{- is distributed to (1 - 2i) & - is distributed to (1- 3i)}

= 2 - 1 + 4 + 1 + 2i - 5i + 3i

= 6 +0i = 6

5) 4 - 3i + 4 + 3i = 4 +4 -3i + 3i

= 8

7) (3 - 2i)² + (3 +2i) = 3² - 2*3*2i + (2i)² + 3 + 2i {(a - b)² = a² - 2ab +b²}

= 9 -12i + 4i² + 3 + 2i

= 9 - 12i + 4*(-1) + 3 + 2i {i² = -1}

= 9 +3 - 4 - 12i +2i

= 8 - 10i

$9) (a +b)^{4} - (a - b)^{4} = 8ab(a^{2} +b^{2})\\\\\\Here, \ a = 1 \ and \ b = i\\\\\\(1+\sqrt{-1})^{4}-(1-\sqrt{-1})^{4}=(1+\sqrt{i^{2}})^{4}-(1-\sqrt{i^{2}})^{4}\\\\=(1+i)^{4}-(1-i)^{4}\\\\=8*1*i(1^{2}+i^{2})\\\\=8i*(1 -1)\\\\=8i*0\\\\=0$

6 0

3 years ago