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3 years ago

What is the slope of the line through the given points:

Mathematics

2 answers:

bekas [8.4K]3 years ago

4 0

Answer:

Step-by-step explanation:

-4 -1 -5

__ - ___ = ___ = 5

-2 1 -1

telo118 [61]3 years ago

3 0

Answer: slope is 1

equation: 1x-2 or x-2

I hope this is good enough:

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Which of the following is the correct

vekshin1

Answer:

which of what? no answer choices.

3 0

3 years ago

At a bargain store, Tanya bought three items that each cost the same amount. Tony bought four items that each cost the same amou

djverab [1.8K]

Each of Tony’s items are $7.65
Each of Tanyas items are $10.2

5 0

3 years ago

The graph of the continuous function g, the derivative of the function f, is shown above. The function g is piecewise linear for

4vir4ik [10]

A) $g=f'$ is continuous, so $f$ is also continuous. This means if we were to integrate $g$ , the same constant of integration would apply across its entire domain. Over $0$ , we have $g(x)=2x$ . This means that

$f_{0$

For $f$ to be continuous, we need the limit as $x\to1^-$ to match $f(1)=3$ . This means we must have

$\displaystyle\lim_{x\to1}x^2+C=1+C=3\implies C=2$

Now, over $x$ , we have $g(x)=-3$ , so $f_{x$ , which means $f(-5)=17$ .

b) Integrating over [1, 3] is easy; it's just the area of a 2x2 square. So,

$\displaystyle\int_1^6g(x)=4+\int_3^62(x-4)^2\,\mathrm dx=4+6=10$

c) $f$ is increasing when $f'=g>0$ , and concave upward when $f''=g'>0$ , i.e. when $g$ is also increasing.

We have $g>0$ over the intervals $0$ and $x>4$ . We can additionally see that $g'>0$ only on $0$ and $x>4$ .

d) Inflection points occur when $f''=g'=0$ , and at such a point, to either side the sign of the second derivative $f''=g'$ changes. We see this happening at $x=4$ , for which $g'=0$ , and to the left of $x=4$ we have $g$ decreasing, then increasing along the other side.

We also have $g'=0$ along the interval $-1$ , but even if we were to allow an entire interval as a "site of inflection", we can see that $g'>0$ to either side, so concavity would not change.

5 0

3 years ago

The sum of two numbers is 64. The difference between the numbers is 14. Write a system

Anastasy [175]

Answer:

They say that the sum of the two numbers (x and y) is 64, so we can write our first equation by adding them and setting that sum equal to 64:

x + y = 64

The question also tells us that their difference is 14. Similarly to before, we'll just subtract the two numbers and set that difference equal to 14:

x - y = 14

Now from here, you know how to continue with substitution to find the values for x and y. Just remember when you get a word problem to break it down and look for key words like sum, difference, or product, and from there you'll be able to build your system of equations.

8 0

2 years ago

Point T has coordinates (10,20). To calculate the coordinates of point T′ in the image,

Hatshy [7]

Answer: $T'(18,36)$

Step-by-step explanation:

For this exercise it is important to know the definition of "Dilation".

A Dilation is defined as a transformation in which the Image (The figure obtained after the transformation) and the Pre-Image (The original figure before the transformation) have the same shape but have different sizes.

If the Dilation is centered at the origin, and knowing the scale factor of $\frac{9}{5}$ , you need to multiply each coordinate of the point T by the scale factor in order to find the coordinates of the Image T'.

Knowing that the point T has the following coordinates:

$T(10,20)$

You get that the coordinates of the Image T' are the shown below:

$T'=(\frac{9}{5}*10,\frac{9}{5}*20)\\\\T'=(18,36)$

6 0

3 years ago