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Veronika [31]
3 years ago
5

Simplify the the expression (4x^4y)^2*2x^3y^4

Mathematics
1 answer:
Elden [556K]3 years ago
4 0

Answer: 32x^11 y^6

If you are still confused just let me know i will do it step by step :)

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A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acc
alexdok [17]
The equation is:
h ( t ) = - 16 t² + 60 t + 3
The toy rocket will reach the ground when: h ( t ) = 0
- 16 t² + 60 t + 3 = 0
t _{12} =  \frac{-60+/- \sqrt{3600+192} }{-32}
t 1 = - 0.05
t 2 = 3.8
Answer:
C ) 3.80 s

3 0
3 years ago
(GRAPH BELOW)
Rainbow [258]

Answer:

The tap drains approximately half the water from the tank in 15 minutes

The tank initially has 50 gallons of water

Step-by-step explanation:

<u>The tap drains approximately half the water from the tank in 15 minutes. </u><u>True.</u>

This is true because see that the point (15,25) lies on the graph of the line.

Which means after 15 minutes the amount of water left in the tank is 25 gallons and 25 is half of 50.

The tap drains exactly one gallon from the tank every minute. False

This is false because the slope of the graph is m=\frac{50-25}{0-15}=-\frac{5}{3}

<u>The tank initially has 30 gallons of water. </u><u>False.</u>

The y-intercept is the initial gallons of water which is 50.

<u>The tank initially has 50 gallons of water. </u><u>True.</u>

The y-intercept is the initial gallons of water which is 50.

<u>The tank takes 50 minutes to drain completely. </u><u>False</u><u>.</u>

It is false because the x-intercept tells us the tank is drained completely and it is not 50 minutes but rather 30 minutes.

4 0
3 years ago
Each of n specimens is to be weighed twice on the same scale. Let Xi and Yi denote the two observed weights for the ith specimen
Setler [38]

Answer:

attached below

Step-by-step explanation:

Attached below is a detailed solution to your problem above

a) show that the maximum likelihood estimator of Ï2 is Xi and Yi.

attached below is the detailed solution

8 0
3 years ago
I need help solving this trig problem w/ identites.
Charra [1.4K]
\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\\\&#10;tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\qquad \qquad sec(\theta)=\cfrac{1}{cos(\theta)}&#10;\\\\&#10;-------------------------------

\bf \cfrac{1}{sin(x)-1}+\cfrac{1}{sin(x)+1}\implies \cfrac{sin(x)+1~~+~~sin(x)-1}{[sin(x)-1][sin(x)+1]}&#10;\\\\\\&#10;\cfrac{2sin(x)}{\stackrel{\textit{difference of squares}}{sin^2(x)-1^2}}\implies \cfrac{2sin(x)}{sin^2(x)-1}\implies \cfrac{2sin(x)}{-[~1-sin^2(x)~]}&#10;\\\\\\&#10;\cfrac{2sin(x)}{-[cos^2(x)]}\implies -2\cdot \cfrac{sin(x)}{cos(x)}\cdot \cfrac{1}{cos(x)}\implies -2tan(x)sec(x)
3 0
3 years ago
35.99 divided by 15.6
olasank [31]

Answer:

around 2.31

Step-by-step explanation:

because you will get 2.307 if you put it in a calculator then you can round it to 2.31

8 0
2 years ago
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