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Paul [167]
2 years ago
8

what is the equation of the line in standard form through each point? (3,1) & perpendicular to -4c + y - 1= 0

Mathematics
2 answers:
ad-work [718]2 years ago
5 0
C = 1/4 y + -1/4 is the answer
kkurt [141]2 years ago
3 0
You already got the answer to late
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Find the angles x and y in following figure.....correct answer will be mark BRAINLIEST and be followed...​
olga2289 [7]

Answer:

<CTS=180-(35+31) (sum of <s in a triangle)

=180-66

=114 degrees

x=180-114 (angles on a straight line)

x=66 degrees

<TSR=180-(30+36)

=180-66

=114 degrees

<TSA=180-114

=66 degrees

y=180-(66+66)

y=180-132

y=48 degrees

3 0
3 years ago
On his 8 tests, Hong earned a total of 568 points. What was his mean number if points earned per test?
madam [21]

Answer:

He earned 71 points per test on average.

Step-by-step explanation:

Divide the total amount of points by the amount of tests to find the average (mean.)

6 0
3 years ago
A car's rear windshield wiper rotates 130°. The total length of the wiper mechanism is 25 inches and the length of the wiper bla
Delicious77 [7]

The area wiped by the viper blade is approximately 486.7 square inches.

The area wiped by the wiper blade (A), in square inches, is equal to the area of the circular section described below:

A = \frac{\theta\cdot \pi}{360}\cdot (R^{2}-r^{2}) (1)

Where:

  • \theta - Angle, in sexagesimal degrees.
  • r - Inner radius, in inches.
  • R - Outer radius, in inches.

If we know that \theta = 130^{\circ}, R = 25\,in and r = 14\,in, then the area wiped by the wiper blade is:

A = \frac{130\pi}{360} \cdot [(25\,in)^{2}-(14\,in)^{2}]

A \approx 486.7\,in^{2}

The area wiped by the viper blade is approximately 486.7 square inches.

We kindly invite to check this question on circular sections: brainly.com/question/14989543

8 0
2 years ago
Tyler is thinking of a number that is divisible by 2 and by 3. Write another number in which Tyler's number must also be divisib
Mumz [18]

Answer:

6

Step-by-step explanation:

6 because 6/2=3,6/3=2

3 0
2 years ago
After a glide reflection, the point x is mapped to the point x' (3,-2). The translation part of the glide reflection is (x,y) -&
Umnica [9.8K]

The coordinates of the original point <em>x</em>, can be obtained by reversing the given transformations individually

The coordinates of the original point <em>x</em> is \underline{(0, \, 0)}

Reason:

The type of reflection = Glide reflection

Coordinates of the image of the point <em>x</em> = x'(3, -2)

The translation part of the glide reflection is (x, y) → (x + 3, y)

The line of reflection is y = -1

The coordinates of the original point = Required

Solution:

  • A glide reflection is also known as a transflection, that involves a symmetric composite transformation of a reflection followed by a translation along the line of reflection

Reflection part;

The distance of the image point from the reflecting line = The object's

point distance from the reflecting line

Therefore, given that the reflecting line is the line y = -1, and the image

point is x'(3, -2), we have;

Distance of image from reflecting line =-1 - (-2) = 1

∴ Distance of object point from reflecting line = 1

y-coordinate of object point = -1 + 1 = 0

Point of image of the object before reflection and after translation = (3, 0)

Translation part;

The translation of the glide reflection is (x, y) → (x + 3, y)

Therefore, the location of the object before translation is ((x + 3) - 3, y), which from the point (3, 0) gives, ;

((3) - 3, 0) → (0, 0)

The coordinates of the original point <em>x</em> is \underline{(0, \, 0)}

Learn more here:

brainly.com/question/12890981

8 0
1 year ago
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