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Paul [167]
3 years ago
8

what is the equation of the line in standard form through each point? (3,1) & perpendicular to -4c + y - 1= 0

Mathematics
2 answers:
ad-work [718]3 years ago
5 0
C = 1/4 y + -1/4 is the answer
kkurt [141]3 years ago
3 0
You already got the answer to late
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(x+7)^2+9=0<br><br> Find x with quadratics
Ne4ueva [31]

Answer:

x = -7 ±3i

Step-by-step explanation:

(x+7)^2+9=0

Subtract 9 from each side

(x+7)^2+9-9=0-9

(x+7)^2=-9

Take the square root of each side

sqrt((x+7)^2) = ±sqrt(-9)

We know sqrt(ab) = sqrt(a) sqrt(b)

x+7 = ±sqrt(-1) sqrt(9)

We know that sqrt(-1) is the imaginary number i

x+7 = ±i *3

x+7 =±3i

Subtract 7 from each side

x+7-7 = -7 ±3i

x = -7 ±3i

6 0
3 years ago
Read 2 more answers
Help me please 8th grade khan academy virticle angles
ivanzaharov [21]
The answer is 62^ it reflects angle IK
8 0
2 years ago
What is the length of
saveliy_v [14]

Answer:

17 units

Step-by-step explanation:

Because the triangle is isosceles, 2 of its sides are congruent; namely, the two sides that are opposite of the 2 congruent angles are contruent.

Because of the reason stated above, we can see that AC is congruent to BC, meaning that:

x+9=2x-8

-x      -x

9=x-8

+8  +8

17  = x

Notice that BC is equal to x, so 17 is our final answer.

6 0
2 years ago
Given that (-8,- 7) in on the graph of f(x), find the corresponding point for the fuction f(x -4)
kiruha [24]
The point (x1,y1) on the graph of f(x) is the point (x1-a,y1) for the function
f(x+a)

(-8,-7)=(x1,y1)→x1=-8, y1=-7
f(x-4)=f(x+a)→a=-4

(x1-a, y1)=(-8-(-4), -7)=(-8+4, -7)=(-4,-7)

<span>The corresponding point for the fuction f(x -4) is (-4,-7)</span>
8 0
3 years ago
When Shanaje baby-sits her nephews, she charges $8 plus $4 per hour. If
Vlad1618 [11]
4h +8=20
Hours worked times rate paid plus 8 must equal 20
3 0
3 years ago
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