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Mars2501 [29]
3 years ago
11

there are about 290 kids in a school. if there are 14 teachers and 5 subs how many kids would be in a class with teachers and su

bs?
Mathematics
2 answers:
Korolek [52]3 years ago
7 0
If there is 290 kids,14 teachers, and 5 subs the you have to do adding
                            There is 309 kids with teachers and subs! Hope it               209                          helps! Happy Halloween!!!
  14
<u>+  5
</u> 309<u>
</u>
Bumek [7]3 years ago
3 0
Actually I think it is asking how many kids are in a class with a teacher or sub in that case you would divide 19 (subs and teachers) by 290 (kids) and you get 32.2 repeating happy Halloween
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zubka84 [21]

Answer:  The required answers are

(a) 0.25,    (b) 0.62,    (c) 6.

Step-by-step explanation:  Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.

(a) The probability of getting 5 heads is given by

P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.

(b) The probability of getting 5 or more than 5 heads is

P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

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3 years ago
Two numbers have a sum of 93. If one number is p, express the other number in terms of p.
Naddik [55]

Answer:

4

Step-by-step explanation:


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Answer: 16/35, decimal form: 0.45

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At the point/angle E:

- the adjacent side(side <u>next to</u> the point/angle) is ED

- the opposite side(side of the triangle <u>across</u> from the point/angle) is DF

- the hypotenuse (the<u> longest side</u> of the triangle) is EF.


sin ∠E = \frac{opposite}{hypotenuse}

sin ∠E = \frac{6}{10} = \frac{3}{5} (simplified)

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Answer: 8000700

Step-by-step explanation:

10 to the 6th power is 100000

1000000 * 8.0007 = 8000700

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