Let "a" and "b" be some number where:
a - b = 24
We want to find where a^2 + b^2 is a minimum. Instead of just logically figuring out that the answer is where a=b=12, I'll just use derivatives.
So we can first substitute for "a" where a = b+24
So we have (b+24)^2 + b^2 = b^2 +48b +576 + b^2
And that equals 2b^2 +48b +576
Then we take the derivative and set it equal to zero:
4b +48 = 0
4(b+12) = 0
b + 12 = 0
b = -12
Thus "a" must equal 12.
So:
a = 12
b = -12
And the sum of those two numbers squared is (12)^2 + (-12)^2 = 144 + 144 = 288.
The smallest sum is 288.
Answer:
15 miles
Step-by-step explanation:
5 days times 3 miles per day.
the saturdat/Sunday skateboarding stuff is irrelevant to the question asked
Answer:
A
Step-by-step explanation:
The absolute value of -30 is 30. -15 is less than half of that because half of 30 is 15 and -15 is less than that.
Hope this helped and have a great day!
(Vote this brainliest please)
<span>Trinomial Ax^2 + Bx + C is perfect square if:
A > 0
C > 0
B = ±2√A√C
36b^2 − 24b − 16
C < 0
4a^2 − 10a + 25
2√A√C = 2*2*5 = 20,
B = −10
16x^2 + 24x − 9
not perfect square,
C < 0
4x^2 − 12x + 9
perfect square:
A>0,
C>0,
2√A√C
= 2*2*3
= 12
= -B
= (2x − 3)^2
hope this helps</span>
