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3 years ago

What is the solution? y = 3x - 5 y = 1\3*+3

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

3 0

Answer:

Step-by-step explanation:

y = 3x - 5

y = 1/3x + 3

3x - 5 = 1/3x + 3....multiply everything by 3 to get rid of the fraction

9x - 15 = x + 9

9x - x = 9 + 15

8x = 24

x = 24/8

x = 3

y = 3x - 5

y = 3(3) - 5

y = 9 - 5

y = 4

solution is : x = 3 and y = 4...or (3,4) <==

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3 years ago

Tobeg says the equation 3x + 2y= 270 and y=4/5x + 20 intersect at the point (50,60) is this true how do you know

il63 [147K]

ANSWER

Yes it is very true

<u>EXPLANATION</u>

If the two equations intersect at $(50,60)$ then this point must satisfy the two equations.

$3x+2y=270---(1)$

We substitute $(50,60)$ in to erquation (1)

$3(50)+2(60)=270$

$150+120=270$

$270=270$

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We now substitute $(50,60)$ in to erquation (2) also

$60=\frac{4}{5}(50)+20$

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Since the point satisfy all the two equations, it is true that they intersect at $(60,50)$

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3 years ago

Find the quotient of 4/15 ÷ 1/6

Molodets [167]

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3 years ago

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