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Darina [25.2K]
4 years ago
7

What is the solution of 7k+2=4k-10? (anwser asap plz)

Mathematics
2 answers:
inysia [295]4 years ago
7 0

Answer:

3

Step-by-step explanation:

LuckyWell [14K]4 years ago
7 0

Answer:

k = -4

division property

Step-by-step explanation:

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What is 2x-3y=-1 <br> y=x-1
Vika [28.1K]
If you're looking for the solution to the system of equations, here's how we solve using substitution
We know that y = x - 1, so we can plug that into the first equation giving
2x - 3(x-1) = -1
Now distribute the 3 giving 2x - 3x + 3 = -1. After combining like terms we get -x + 3 = -1. Now subtract 3 from both sides, -x = -4, and multiply both sides by -1 to make x positive. x = 4
Now we can plug that into the second equation to get y
y = x - 1, and we know that x = 4, so y = 4 - 1, y = 3. The solution is (4, 3)
8 0
3 years ago
Read 2 more answers
What is the distributive property of 36÷3
olya-2409 [2.1K]
12 is the answer your looking for
7 0
3 years ago
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Write the formula for the area of a triangle, A=1/2bh in terms of h. Find the height of a triangle when A = 18 in. squared and b
Elena L [17]

The height of the given triangle is  

5 0
4 years ago
Zohar is using scissors to cut a rectangle with a length of 5x - 2 and a width of 3x + 1 out of a larger piece of paper. Which
kirza4 [7]

Answer:

2*(5x - 2) + 2*(3x+1) ; Perimeter = 62 centimeters

Step-by-step explanation:

2*(5x - 2) + 2*(3x+1) = 10x - 4 + 6x + 2

                                = 16x -2

If x = 4 , then Perimeter = 16*4 - 2 = 64 - 2 = 62 cm

4 0
4 years ago
Read 2 more answers
At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is
Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = \frac{dx}{dt}

ship B is sailing north at 20 km/h =\frac{dy}{dt}

here x and y are the  sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

                 y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find \frac{dz}{dt} at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we |  | get \\

z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h

derivative first equation w . r. to t we get

2z\frac{dz}{dt} =-2(130-x)\frac{dx}{dt}+2y\frac{dy}{dt}

\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]

\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }

     = \frac{1100}{85.44}\\  = 12.87km/h

8 0
3 years ago
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