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marishachu [46]
3 years ago
13

The building of the Blue Museum of Barcelona is triangular. Each side of the building is 180 m. How far do we have to travel to

go around it completely (perimeter)?
Mathematics
1 answer:
Sever21 [200]3 years ago
6 0

Answer:

540 m

Step-by-step explanation:

The building of the Blue Museum of Barcelona is triangular and each side of the building is 180 m.

This means the building is shaped as an equilateral triangle.

We need to find the total distance traveled if we go round the building, that is, its perimeter.

The perimeter of an equilateral triangle is given as:

P = 3L

where L = length of the side of the building = 180 m

The total distance traveled if we go round the building will be:

P = 3 * 180 = 540 m

We would need to go 540 m to travel around the building completely.

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Y = (x)^(1/9)*Find f(x) when x=(1/2)Round your answer to the nearest thousandth.
Verizon [17]

We are given a function f ( x ) defined as follows:

y=f(x)=x^{\frac{1}{9}}

We are to determine the value of f ( x ) when,

\times\text{ = }\frac{1}{2}

In such cases, we plug in/substitue the given value of x into the expressed function f ( x ) as follows:

y\text{ = f ( }\frac{1}{2}\text{ ) = (}\frac{1}{2})^{\frac{1}{9}}

We will apply the power on both numerator and denominator as follows:

f(\frac{1}{2})=\frac{1^{\frac{1}{9}}}{2^{\frac{1}{9}}}\text{ = }\frac{1}{2^{\frac{1}{9}}}

Now we evaluate ( 2 ) raised to the power of ( 1 / 9 ).

f\text{ ( }\frac{1}{2}\text{ ) = }\frac{1}{1.08005}

Next apply the division operation as follows:

f\text{ ( }\frac{1}{2})\text{ = }0.92587

Once, we have evaluated the answer in decimal form ( 5 decimal places ). We will round off the answer to nearest thousandths.

Rounding off to nearest thousandth means we consider the thousandth decimal place ( 3rd ). Then we have the choice of either truncating the decimal places ( 4th and onwards ). The truncation only occurs when (4th decimal place) is < 5.

However, since the (4th decimal place) = 8 > 5. Then we add ( 1 ) to the 3rd decimal place and truncate the rest of the decimal places i.e ( 4th and onwards ).

The answer to f ( 1 / 2 ) to the nearest thousandth would be:

\textcolor{#FF7968}{f}\text{\textcolor{#FF7968}{ ( }}\textcolor{#FF7968}{\frac{1}{2})}\text{\textcolor{#FF7968}{ = 0.926}}

6 0
1 year ago
|(1)
Yanka [14]
So first you would divide 1950/6 to find the amount for one year of their age.
Then you would multiply that by the ages, which should get you 4 numbers, then you all those numbers together. Try 9750.
3 0
3 years ago
Determine which equations have the same solution set as StartFraction 2 Over 3 EndFraction minus x plus StartFraction 1 Over 6 E
Lina20 [59]

Answer:

A, B, F

Step-by-step explanation:

2/3 - x + 1/6 = 6x

Collect like terms

2/3 + 1/6 = 6x + x

(4+1) / 6 = 7x

5/6 = 7x

x = 5/6 ÷ 7

= 5/6 × 1/7

x = 5/42

a) 4 - 6x + 1 = 36x

4 + 1 = 36x + 6x

5 = 42x

x = 5/42

Equivalent to the last step of the simplification above

b) 5/6 - x = 6x

5/6 = 6x + x

5/6 = 7x

This is equivalent to the third step of the simplification

c) 4 - x + 1 = 6x

4 + 1 = 6x + x

5 = 7x

x = 5/7

Not equivalent to any of the steps in the simplification above

d) 5/6 + x = 6x

5/6 = 6x - x

5/6 = 5x

x = 5/6 ÷ 5

= 5/6 × 1/5

x = 5/30

Not equivalent to any of the steps in the simplification above

e) 5 = 30x

x = 5/30

Not equivalent to any of the steps in the simplification above

f) 5 = 42x

x = 5/42

Equivalent to the last step of the simplification above

4 0
3 years ago
Complete The Square:<br> (Z^2)-19z=66
Musya8 [376]
To solve the equation using complete square method we proceed:
z^2-19z=66
but
 c=(-b/2a)^2
c=(-19/2)^2
c=361/4
thus:
z^2-19z+361/4=66+361/4
factoring the LHS we get:
1/4(2z-19)^2=625/4

(2z-19)^2=625
getting the square root of both sides we get:
2z-19=+/-25
2z=+/-25+19
2z=44 or -6
z=22 or -3
Answer: z=22 or z=-3



8 0
3 years ago
If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta
iren [92.7K]
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\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}

\cot\theta= \frac{\cos\theta}{\sin\theta}= \frac{-\frac{3}{5}}{\frac{4}{5}}  =- \frac{3}{4}

5 0
3 years ago
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