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jolli1 [7]
3 years ago
14

A balloon in the air has more energy than??

Chemistry
2 answers:
Svetlanka [38]3 years ago
6 0
Potential energy is the answrt
jeka57 [31]3 years ago
6 0
Potential energy is the answer
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The density of gold is 19.3 g/cm3. What is the volume of a 13 g gold nugget? (Density: D = ) .25 cm3 .67 cm3 1.48 cm3 2.50 cm3
zhannawk [14.2K]

Answer:

<h3>The answer is 0.67 cm³ </h3>

Explanation:

Density of a substance can be found by using the formula

<h3>Density =  \frac{mass}{volume}</h3>

Making volume the subject we have

<h3>volume =  \frac{mass}{Density}</h3>

From the question

mass of gold nugget = 13 g

Density = 19.3 g/cm³

Substitute the values into the above formula and solve for the volume

We have

<h3>volume  =  \frac{13}{19.3}</h3>

= 0.673575

We have the final answer as

<h2>0.67 cm³</h2>

Hope this helps you

8 0
3 years ago
Read 2 more answers
alculate the standard enthalpy of formation of ethanoic acid given that the standard enthalpy of combustion for carbon is –394 k
agasfer [191]

Answer:

The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.

Explanation:

C(g)+O_2(g)\rightarrow CO_2(g),\Delta H_{1, comb}=-394 kJ/mol...[1]

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l),\Delta H_{2, comb}=-286 kJ/mol..[2]

CH_3COOH(l)+2O_2(g)\rightarrow 2CO_2(g)+2H_2O(l),\Delta H_{3, comb}=-876 kJ/mol..[3]

The standard enthalpy of formation of ethanoic acid :

2C(g)+2H_2(g)+O_2(g)\rightarrow CH_3COOH, \Delta H_{4}=?..[4]

Using Hess's law to calculate :

2 × [1] + 2 × [2] - [3] = [4]

\Delta H_4=2\times (-394 kJ/mol)+2\times (-286 kJ/mol) - (-876 kJ/mol)

=\Delta H_4=-484 kJ/mol

The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.

5 0
3 years ago
PLEASE HELP ME WITH ATOMS AND DALTON I BEG YOU
rosijanka [135]

Dalton's atomic theory was the first complete attempt to describe all matter in terms of atoms and their properties.

Dalton based his theory on the law of conservation of mass and the law of constant composition.

The first part of his theory states that all matter is made of atoms, which are indivisible.

The second part of the theory says all atoms of a given element are identical in mass and properties.

The third part says compounds are combinations of two or more different types of atoms.

The fourth part of the theory states that a chemical reaction is a rearrangement of atoms.

Parts of the theory had to be modified based on the discovery of subatomic particles and isotopes.


6 0
3 years ago
If 152 grams of ethane (c2h6) are reacted with 231 grams of oxygen gas, what is the mass of the excess reactant leftover after t
Naya [18.7K]
Answer is: <span>the mass of the excess reactant (ethane) leftover is 90.135 grams.
</span>Chemical reaction: 2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O<span>(g).
m(</span>C₂H₆) = 152 g.
n(C₂H₆) = m(C₂H₆) ÷ M(C₂H₆).
n(C₂H₆) = 152 g ÷ 30 g/mol.
n(C₂H₆) = 5.067 mol.
m(O₂) = 231 g.
n(O₂) = 231 g ÷ 32 g/mol.
n(O₂) = 7.218 mol; limiting reactant.
From chemical reaction: n(O₂) : n(C₂H₆) = 7 : 2.
n(C₂H₆) = 2 · 7.218 mol ÷ 7.
n(C₂H₆) = 2.0625mol.
Δn(C₂H₆) = 5.067 mol - 2.0625 mol.
Δn(C₂H₆) = 3.0045 mol.
Δm(C₂H₆) = 3.0045 mol · 30 g/mol = 90.135 g.
6 0
4 years ago
Read 2 more answers
How many moles are in 4561 g of C3H7OH?
d1i1m1o1n [39]

Answer: 76.017 moles

Explanation:

3 0
3 years ago
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