Answer:
wavelength = 0.534×10⁻¹⁶ m
Explanation:
Given data:
Frequency of wave = 5.62 ×10²⁴ Hz
Wavelength = ?
Solution:
Speed of photon = wavelength × frequency
wavelength = speed of photon / frequency
Now we will put the values in formula:
wavelength = 3×10⁸ m/s / 5.62 ×10²⁴ Hz
Hz = s⁻¹
wavelength = 3×10⁸ m/s / 5.62 ×10²⁴ s⁻¹
wavelength = 0.534×10⁻¹⁶ m
A!
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<u>Answer:</u> The wavelength of the flame is 462 nm and color of cesium flame is blue.
<u>Explanation:</u>
To calculate the wavelength, we use Planck's equation, which is:

where,
E = Energy of 1 photon = 
h = Planck's constant = 
c = speed of light = 
= wavelength = ?
Putting values in above equation, we get:

The range of wavelength of blue light lies in range of 500 nm - 435 nm
The calculated wavelength lies in the above range. So, the color of the cesium flame is 462 nm
Hence, the wavelength of the flame is 462 nm and color of cesium flame is blue.
B water at 99c since it is the hottest