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omeli [17]
3 years ago
5

Is the group number the number of electrons on the outermost shell ​

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
6 0
In the column have the same electrons on the outer shell. Which the outer shell electrons are call valence electrons.
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75 POINTS AND BRAINLIEST TO WHOEVER ANSWERS FIRST define gravity and provide three examples of gravity in action. What is Newton
rosijanka [135]

Explanation:

the force of attraction towards the centre

of earth or planet is gravity.

for example

  • rock in land
  • flow of river downwards
  • revolution of earth towards the sun

3 0
3 years ago
Calculate the mass percent (m/m) of a solution prepared by dissolving 51.56 g of NaCl in 164.2 g of H2O. Express your answer to
denis-greek [22]

Answer:

"23.896%" is the right answer.

Explanation:

The given values are:

Mass of NaCl,

= 51.56 g

Mass of H₂O,

= 165.6 g

As we know,

⇒  Mass of solution = Mass \ of \ (NaCl+H_2O)

                                 = 51.56+164.2

                                 = 215.76 \ g

hence,

⇒ Mass \ percent =\frac{Mass \ of \ NaCl}{Mass \ of \ solution}\times 100

                           =\frac{51.56}{215.76}\times 100

                           =23.896 \ percent

4 0
3 years ago
) A children’s liquid cold medicine has a density of 1.23 g/mL. If a child is to take 2.5 tsp in a dose, what is the mass in gra
vekshin1

The relation between density and mass and volume is

Density=\frac{Mass}{volume}

the dose required is 2.5 tsp

each tsp contain 5mL

So dose required in mL = 2.5 X 5 = 12.5 mL

the mass will be calculated using following formula

Mass=DensityXvolume

Mass=1.23\frac{g}{mL}X12.5mL= 15.38g

The mass of dose in grams will be 15.38 g


5 0
3 years ago
What type of product forms in the intramolecular reaction between the aldehyde portion of the glucose molecule below and its C-5
djyliett [7]

Question:

What type of product forms in the intramolecular reaction between the aldehyde portion of the glucose molecule below and its C-5 hydroxyl group?  

a. disaccharide

b. carboxylic acid

c. hemiacetal

d. ester

e. stereoisomer

Answer:

hemiacetal  forms in the intramolecular reaction between the aldehyde portion of the glucose molecule and its C-5 hydroxyl group

Explanation:

It is an alcohol also an ether that has been attached to the carbon molecule. Here the hydrogen has occupied the fourth bonding position. This hemiacetal has been derived from the aldehyde. Hence, hemiketal being an alcohol as well as ether has been attached to the same carbon and also to the two other carbon.

7 0
3 years ago
Answer my question please!
Elza [17]
I think it is B! I am so sorry if it’s wrong, love.
5 0
3 years ago
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