1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Katarina [22]
3 years ago
13

Write a loop that reads c-strings from standard input where the c-string is either "land", "air", or "water". The loop terminate

s when "xxxxx" (five x characters ) is read in. Other strings are ignored. After the loop, your code should print out 3 lines: the first consisting of the string "land:" followed by the number of "land" strings read in, the second consisting of the string "air:" followed by the number of "air" strings read in, and the third consisting of the string "water:" followed by the number of "water" strings read in. Each of these should be printed on a separate line. Assume that the maximum length of a string is 8.

Computers and Technology
1 answer:
Anvisha [2.4K]3 years ago
3 0

Answer:

I am writing a C++ code.        

#include <iostream> // for input output functions

using namespace std; // identifies objects like cin cout

int main() { //start of main() function body

string c_string; // stores the string entered by user from land water or air

int land=0; // contains the number of times land string is read in

int air=0; //contains the number of times air string is read in

int water = 0; //contains the number of times water string is read in

cin>>c_string; //reads the string entered by user from air water or land

/*while loop continues to execute until user enters xxxxx or maximum length of a string exceeds 8 */

while(c_string!= "xxxxx" && c_string.length()<=8) {

if(c_string=="land"){ // if string entered by user is land

land = land + 1;} //counts and increments each occurrence of land string by 1

else if(c_string=="air"){// if string entered by user is air

air = air + 1;}// counts and increments each occurrence of string air by 1

else if(c_string=="water"){// if string entered by user is water

water = water + 1;}//counts and increments each occurrence of air by 1

cin>>c_string;}

/* keeps reading the string entered by user from land air or water, until the loop breaks after the user enters xxxxx or user enters a string whose length is greater than 8 */

//prints the number of times land, air and water are read in

cout << "land:"<<land;

cout << endl<<"air:"<<air;

cout << endl<< "water:"<<water; }                      

                                                                                     

Explanation:

Everything is well explained in the comments above.

The program prompts the user to input strings. These strings are either land air or water. The while loop continues to read the input strings until user enters xxxxx or the string entered by user exceeds the length 8. Both these terminating conditions are added in the while loop. After the loop terminates, the number of times land, air and water strings are read is displayed on the output screen. Any other string entered by user other than these 3 is ignored. The program along with the output is attached.

You might be interested in
Instructions The population of town A is less than the population of town B. However, the population of town A is growing faster
weeeeeb [17]

Answer: The c++ program is given below.

#include <iostream>

using namespace std;

int main() {

float townA, townB, growthA, growthB, populationA, populationB;

    int year=0;    

cout<<"Enter present population of town A : ";

cin >> townA;  

cout<<endl<<"Enter present growth rate of town A : ";

cin >> growthA;

growthA = growthA/100;  

cout<<endl<<"Enter present population of town B : ";

cin >> townB;  

cout<<endl<<"Enter present growth rate of town B : ";

cin >> growthB;

growthB = growthB/100;  

do

{

    populationA = townA + (townA * growthA);

    populationB = townB + (townB * growthB);      

    townA = populationA;

    townB = populationB;      

    year++;      

}while(populationA < populationB);  

cout<<endl<<"After " <<year<< " years, population of town A is "<<populationA << " and population of town B is "<< population<<endl;

return 0;

}

Explanation:

All the variables for population and growth rate are declared with float datatype.

The user inputs the present population of both the towns.

The growth rate entered by the user is the percentage growth.

For example, town A has 10% growth rate as shown in the output image.

The program converts 10% into float as 10/100.

growthA = growthA/100;

growthB = growthB/100;

The above conversion is done to ease the calculations.

The year variable is declared as integer and initialized to 0.

The growth in population is computed in a do-while loop. After each growth is calculated, the year variable is incremented by 1.

The loop continues until population of town A becomes greater than or equal to population of town B as mentioned in the question.

Once the loop discontinues, the final populations of town A and town B and the years needed for this growth is displayed.

The new line is introduced using endl keyword.

The function main has return type int hence, 0 is returned at the end of the program.

6 0
3 years ago
Please someone helppppppp
Cerrena [4.2K]

Answer : communicate is the answer.

5 0
3 years ago
Read 2 more answers
Virtualization, like cloud computing, is a technology that can be useful for _____ sites. hot warm business cold
natima [27]

Answer: Hot sites

Explanation:

 Virtualization in the cloud computing is the technology that are useful for the hot sites. It basically making the virtual image of the network devices so that it can be easily use multiple machine at the similar time.

There are various types of benefits of the virtualization in the cloud computing are as follow:

  • It protect the system from the system failure.
  • It is the cost effective technology.
  • By using this we can easily transfer the data from the physical storage to the virtual server.
8 0
3 years ago
A small amount of memory stored on the central processor for easy access is called
expeople1 [14]

The answer is : Cache.  It is a small amount of memory stored on the central processor for easy access.  Cache is where active data are placed for easier access, it stores recently used information so that it can be quickly accessed at a later time. Some types of cache are browser cache, disk cache, memory cache, and processor cache.

3 0
3 years ago
Read 2 more answers
Additional rows and columns are inserted into a table using the
Paladinen [302]
The Option D , Table Tools Insert
6 0
2 years ago
Other questions:
  • Calls to the tostring( ) method emphasize the use of ____.
    12·1 answer
  • Prompt the user to input an integer, a double, a character, and a string, storing each into separate variables. Then, output tho
    9·1 answer
  • The primary key is a field that uniquely and completely identifies a record.
    14·2 answers
  • What conversion factor should be used to convert from meters to Gigameters?
    7·1 answer
  • Is USA TestPrep a test-taking site that won't let you access other windows without kicking you off?
    13·1 answer
  • Using complete sentences post a detailed response to the following.
    13·1 answer
  • 6.16 LAB: Find largest number (EO) Write a method, findMax(), that repeatedly reads in integers until a negative integer is read
    9·1 answer
  • Miley met up with a bunch of her college friends after several years. She told them that she works for the sound department of a
    5·1 answer
  • Direction: using the data at the left, answer the questions that follows.​
    11·1 answer
  • Alfred works in the human resources department, and he uses a management information system to find applicants' résumés on the w
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!