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motikmotik
3 years ago
5

The marked price of an article is 30% above it's selling price and the cost price is 35%less than it's marked price. find the di

scount percent and gain percent​
Mathematics
1 answer:
SashulF [63]3 years ago
8 0

Answer:

Let C be the cost price of the article. Then:

C(1+30%)=marked price

So:

C(1+30%)=C(1.3)

=1.3C

If the article is then marked down 35%, then its’ price would be:

1.3C(1–35%)=1.3C(.65)

=0.845 or 84.5% of its’ cost

Then:

0.845–1=-0.155

or, a 15.5% loss on the item

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Half of Robert's piece of wire is equal to 2 thirds of Maria's wire. The total length of their wires is 10 feet. How much longer
Yuliya22 [10]

Answer:

let x be the Robert piece

y Maria's piece

x+y=10

0,5*x ( half of Robert piece)= 2/3 y( 2 thirds)

2 equations then

x+y= 10 then x= 10-y

0,5x= 0,67 y  then we replace x by 10-y on the second equation and it gives

0,5(10-y)= 5-0,5y=0,67y

5= 1,17 y so y= 4,27    and then x= 10-y= 5,73

the question asks how much Robert wire is longer than Maria's wire

so we get x-y= 1,46


6 0
4 years ago
Read 2 more answers
Construct an Argument:<br> Which is greater, 40 x 1/4 or 40 divided by 1/4? EXPLAIN.
Pani-rosa [81]

Answer:

40 × 1/4

Step-by-step explanation:

That is greater because 40 is being multiplied.

7 0
3 years ago
Read 2 more answers
at food mart, hot dogs can be purchased in packages of 8 for $2.40 or packages of 12 for $3.00. which is a better buy? explain h
olasank [31]

Answer:

12-hot dog package is better buy because the per hot dog price is 5 cents cheaper

Step-by-step explanation:

2.40/8 = 0.30 per hot dog

3.00/12 = 0.25 per hot dog (this is the better buy by $.05)

4 0
3 years ago
Read 2 more answers
Prove that: [1 + 1/tan²theta] [1 + 1/cot² thata] = 1/(sin²theta - sin⁴theta]
Stels [109]

Step-by-step explanation:

<h3><u>Given :-</u></h3>

[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]

<h3><u>Required To Prove :-</u></h3>

[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)

<h3><u>Proof :-</u></h3>

On taking LHS

[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]

We know that

Tan θ = 1/ Cot θ

and

Cot θ = 1/Tan θ

=> (1+Cot²θ)(1+Tan²θ)

=> (Cosec² θ) (Sec²θ)

Since Cosec²θ - Cot²θ = 1 and

Sec²θ - Tan²θ = 1

=> (1/Sin² θ)(1/Cos² θ)

Since , Cosec θ = 1/Sinθ

and Sec θ = 1/Cosθ

=> 1/(Sin²θ Cos²θ)

We know that Sin²θ+Cos²θ = 1

=> 1/[(Sin²θ)(1-Sin²θ)]

=> 1/(Sin²θ-Sin²θ Sin²θ)

=> 1/(Sin²θ - Sin⁴θ)

=> RHS

=> LHS = RHS

<u>Hence, Proved.</u>

<h3><u>Answer:-</u></h3>

[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)

<h3><u>Used formulae:-</u></h3>

→ Tan θ = 1/ Cot θ

→ Cot θ = 1/Tan θ

→ Cosec θ = 1/Sinθ

→ Sec θ = 1/Cosθ

<h3><u>Used Identities :-</u></h3>

→ Cosec²θ - Cot²θ = 1

→ Sec²θ - Tan²θ = 1

→ Sin²θ+Cos²θ = 1

Hope this helps!!

7 0
3 years ago
What is the range of f(x)=lxl-6?
madam [21]
If the domian is 1 then range is -5
5 0
3 years ago
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