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ch4aika [34]
3 years ago
14

Really need help on today's assignment 5a+ 6(6a+2)

Mathematics
1 answer:
Alisiya [41]3 years ago
6 0

Answer: 5a + 36a + 12

Step-by-step explanation:

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Answer:

BN=4\ \text{in}

AN=2\ \text{in}

AC=\sqrt{5}\ \text{in}

Step-by-step explanation:

Let BN=x

BC=c

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AC=b

We have the relation

\dfrac{BC}{AB}=\dfrac{AB}{BN}\\\Rightarrow \dfrac{c}{a}=\dfrac{a}{x}\\\Rightarrow c=\dfrac{a^2}{x}\\\Rightarrow x+1=\dfrac{a^2}{x}\\\Rightarrow x^2+x=20\\\Rightarrow x^2+x-20=0\\\Rightarrow x=\frac{-1\pm \sqrt{1^2-4\times 1\times \left(-20\right)}}{2\times 1}\\\Rightarrow x=4,-5

\boldsymbol{BN=4\ \text{in}}

h=\sqrt{a^2-x^2}\\\Rightarrow h=\sqrt{(2\sqrt{5})^2-4^2}\\\Rightarrow h=2\ \text{in}

\boldsymbol{AN=2\ \text{in}}

b=\sqrt{h^2+y^2}\\\Rightarrow b=\sqrt{2^2+1^2}\\\Rightarrow b=\sqrt{5}\ \text{in}

\boldsymbol{AC=\sqrt{5}\ \text{in}}

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