Answer:
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The following expressions shows a
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Answer:
Step-by-step explanation:
To solve for q, we initially place everything with the term q to one side of the equality, and everything without the term q to the other side of the equality.
So
We find the square of both sides of the equation. So
Answer:
No invariant point
Step-by-step explanation:
Hello!
When we translate a form, in this case a polygon We must observe the direction of the vector. Since our vector is:
1) Let's apply that translation to this polygon, a square. Check it below:
2) The invariant points are the points that didn't change after the transformation, simply put the points that haven't changed.
Examining the graph, we can see that no, there is not an invariant point, after the translation. There is no common point that belongs to OABC and O'A'B'C' simultaneously. All points moved.
