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Nikitich [7]
3 years ago
13

What does the fundamental theorem of algebra illustrate?

Mathematics
1 answer:
UNO [17]3 years ago
6 0

Answer:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

Step-by-step explanation:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

We have to find the roots of this given equation.

If a quadratic equation is of the form ax^{2}+bx +c=0

Its roots are \frac{-b+\sqrt{b^{2}-4ac } }{2a} and \frac{-b-\sqrt{b^{2}-4ac } }{2a}

Here the given equation is 2x^{2}-4x-1 = 0

a = 2

b = -4

c = -1

If the roots are x_{1} and x_{2}, then

x_{1} = \frac{-2+\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}

                       = \frac{4 +\sqrt{24}}{4}

                       = \frac{2+\sqrt{6} }{2}

x_{2} = \frac{-2-\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}

                        = \frac{4 +\sqrt{8}}{4}

                        = \frac{2-\sqrt{6} }{2}

These are the two roots of the equation.

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Two unidentified flying discs are detected by a receiver. The angle of elevation from the receiver to each disc is 39.48 degree.
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Answer:

The answer is "298.83 m"

Step-by-step explanation:

Its gap from its transmitter from each disc comprises of 2 triangles. Its horizontal segment via disc to vertical, and longitudinal segment. Disk height, h, is parallel to a horizontal disc Wink including its line across recipient to disc or horizontal 39. 48^{\circ}

\to 39. 48^{\circ}  = \frac{h_1}{826 \ m}\\\\   \to 826\ m (\ sin 39. 48^{\circ} ) = h_1\\\\ \to 525.18 = h_1\\\\

if:

\to \sin 39. 48^{\circ} = \frac{h_2}{1.296 \ km}\\\\ \to  \sin 39. 48^{\circ} (1296 \ m) = h_2\\\\  \to  824.01 = h_2\\\\\to                        h_2  - h_1 = 824.01 - 525.18\\\\

                  = 298.83 \ m

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Step-by-step explanation:

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If the diameter of a tree trunk is growing 1/4 inch each year how many years will it take for the diameter to grow 8 inches
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