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Leto [7]
3 years ago
15

The area of a parallelogram is 8√90 the base is 2√5. What is the height of the parallelogram?

Mathematics
2 answers:
Vsevolod [243]3 years ago
3 0

Step-by-step explanation:

Area of the Parallogram =bh

8√90=2✓5*h

12✓2=h

...................

Naddika [18.5K]3 years ago
3 0

Answer:

<h2>The height is 12√2</h2>

Step-by-step explanation:

Area of a parallelogram = base × height

From the question

Area = 8√90

base = 2√5

Substitute the values into the above formula and solve for the height

That's

8 \sqrt{90}  = 2 \sqrt{5} h \\ h =  \frac{8 \sqrt{90} }{2 \sqrt{5} }  \\ h =  \frac{24 \sqrt{10} }{2 \sqrt{5} }

Reduce the fraction with 2

That's

h =  \frac{12 \sqrt{10} }{ \sqrt{5} }

Split √10

We have

h =  \frac{12 \sqrt{2} \times  \sqrt{5}  }{ \sqrt{5} }

Reduce the fraction with√5

We have the final answer as

<h3>12√2</h3>

Hope this helps you

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